Answer:
7.78x10^-8T
Explanation:
The Pointing Vector S is
S = (1/μ0) E × B
at any instant, where S, E, and B are vectors. Since E and B are always perpendicular in an EM wave,
S = (1/μ0) E B
where S, E and B are magnitudes. The average value of the Pointing Vector is
<S> = [1/(2 μ0)] E0 B0
where E0 and B0 are amplitudes. (This can be derived by finding the rms value of a sinusoidal wave over an integer number of wavelengths.)
Also at any instant,
E = c B
where E and B are magnitudes, so it must also be true at the instant of peak values
E0 = c B0
Substituting for E0,
<S> = [1/(2 μ0)] (c B0) B0 = [c/(2 μ0)] (B0)²
Solve for B0.
Bo = √ (0.724x2x4πx10^-7/ 3 x10^8)
= 7.79 x10 ^-8 T
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B precipitation,condensation,precipitation
Answer:
The eight Moon phases:
Waxing Crescent: In the Northern Hemisphere, we see the waxing crescent phase as a thin crescent of light on the right. First Quarter: We see the first quarter phase as a half moon. Waxing Gibbous: The waxing gibbous phase is between a half moon and full moon.
The phases of the Moon are the different ways the Moon looks from Earth over about a month. As the Moon orbits around the Earth, the half of the Moon that faces the Sun will be lit up. The different shapes of the lit portion of the Moon that can be seen from Earth are known as phases of the Moon.
<h2>The 8 phases (in order) are:</h2>
- New moon.
- Waxing Crescent.
- First Quarter.
- Waxing Gibbous.
- Full moon.
- Waning Gibbous.
- Third Quarter.
- Waning Crescent.
Explanation:
Hope it is helpful....
Answer:
1) x_total = 2.7 km=2700 m, 2) t_total = 1926 s, 3) v_avg = 1.40 m / s
Explanation:
1) To solve this uniform velocity problem, we must find the displacement of each part and add them.
x_total = x₁ + x₂
x_total = 0.7 + 2.0
x_total = 2.7 km
2) how long does it take for this tour
truck
v = x₁ / t₁
t₁ = x₁ / v
t₁ = 0.7 / 20
t₁ = 0.035 h
Let's reduce the time to the SI system
t₁ = 0.035 h (3600 s / 1h) = 126 s
when he is walking
t₂ = 30 min (60 s / 1min) = 1800 s
the total time is
t_total = t₁ + t₂
t_total = 126 + 1800
t_total = 1926 s
3) the average velocity is defined as the displacement in the inerval between time
v_avg = x_total / t_total
v_avg = 2700/1926
v_avg = 1.40 m / s