1. Anil leaves home at 0905
2. Anil stays at the park for 10 mins.
3. The distance of Anil's home from the park is 7 km
4. Anil's speed is 14 km/h
The question is a distance-time graph
<h3>What is a distance-time graph?</h3>
A distance-time graph show the relationship between distanced moved by an object and time.
<h3>1. When did Anil leave home?</h3>
Anil left home at the time when the distance is zero. That is, the time at which the graph cuts the time axis. That time is 0905.
So, Anil leaves home at 0905
<h3>2. How many minutes did Anil wait at the park?</h3>
Anil waited at the park when her distance is constant. That is the part of the graph that is parallel to the time axis.
It starts at 0935 and ends at 0945. So, the time anil stays at the park is t = 0945 - 0935 = 10 min.
So, Anil stays at the park for 10 mins.
<h3>3. What is the distance of Anil's home to the park?</h3>
The distance from Anil's home to the park is the maxiimum distance she moves until she reaches the park. From the graph, this is 7 km.
So, the distance of Anil's home from the park is 7 km
<h3>4. What was Anil's speed in his journey to the park?</h3>
Anil's speed in his journey to the park is the gradient of the first slopy line between the points (0905, 0) and (0935, 7)
The gradient, m = (d' - d)/(t' - t) where
- (d,t) = (0905, 0) and
- (t', d') = (0935, 7)
So, m = (d' - d)/(t' - t)
= (7 km - 0 km)/(0935 - 0905) min
= 7 km/30 min
= 7 km/30 min × 60 min/1 hr
= 7 km × 2/hr
= 14 km/h
So, Anil's speed is 14 km/h
Learn more about distance-time graph here:
brainly.com/question/27956440
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