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ahrayia [7]
3 years ago
8

If you make an electromagnet using a battery circuit and a steel nail, how can you increase its magnetic strength?

Physics
2 answers:
Mice21 [21]3 years ago
4 0
<h3><u>Answer;</u></h3>

B.wrap more coils of wire around the nail

<h3><u>Explanation;</u></h3>
  • <em><u>Electromagnets are made by winding a wire through a magnetic material such as soft iron core making a coil, and then passing electric current through the coil thus making the soft iron core magnetic.</u></em>
  • <em><u>The strength of the electromagnet depends on the number of coils and also the size of the electric current through the coil.</u></em>
  • Therefore, in this case wrapping more coils of wire around the nail increases the strength of the electromagnet.
Lilit [14]3 years ago
3 0
The correct answer is B. wrap more coils of wire around the nail. This is how you can increase its magnetic strength. Thank you for posting your question. I hope this answer helped you. Let me know if you need more help. 
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An electric field of intensity 3.80 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.
lakkis [162]

Answer: 1.55 x 10⁴ Nm²c^-1

Explanation: The electric flux, electric field intensity and area are related by the formulae below.

Φ= EAcosθ,

Where Φ= electric flux (Nm²c^-1)

E =electric field intensity (N/m²)

A = Area (m²)

θ= this is angle between the planar area and the magnetic flux

For our question E=3.80KN/c= 3800 N/c

A= 0.700 x 0.350= 0.245m²

θ= 0° ( this is because the electric field was applied along the x axis, thus the electric flux will be parallel to the area).

Hence Φ= 3800 x 0.245 x cos(0)

= 3800 x 0.245 x 1 (value of cos 0° =1)

= 1.55 x 10⁴ Nm²c^-1

Thus the electric field is 1.55 x 10⁴ Nm²c^-1

4 0
3 years ago
If a students clothing catches fire the student should
Roman55 [17]

Answer:

stop, drop and roll.

Explanation:

This is because rolling on the ground can help put out the fire by depriving it of oxygen.

4 0
3 years ago
At a certain instant a particle is moving in the +x direction with momentum +8 kg m/s. During the next 0.13 seconds a constant f
jeka94

Answer:

The momentum of the particle at the end of the 0.13 s time interval is 7.12 kg m/s

Explanation:

The momentum of the particle is related to force by the following equation:

Δp = F · Δt

Where:

Δp =  change in momentum = final momentum - initial momentum

F = constant force.

Δt = time interval.

Let´s calculate the x-component of the momentum after the 0.13 s:

final momentum - 8 kg m/s = -7 N · 0.13 s

final momentum = -7 kg m/s² · 0.13 s + 8 kg m/s

final momentum = 7.09 kg m/s

Now let´s calculate the y-component of the momentum vector after the 0.13 s. Since the particle wasn´t moving in the y-direction, the initial momentum in this direction is zero:

final momentum = 5 kg m/s² · 0.13 s

final momentum = 0.65 kg m/s

Then, the mometum vector will be as follows:

p = (7.09 kg m/s,  0.65 kg m/s)

The magnitude of this vector is calculated as follows:

|p| = \sqrt{(7.09 kg m/s)^{2} + (0.65 kg m/s)^{2}} = 7.12 kg m/s

The momentum of the particle at the end of the 0.13 s time interval is 7.12 kg m/s

4 0
3 years ago
A sled starts off with an initial velocity of 8 m/s and slows down to 2 m/s after 3 seconds. What was its acceleration?
melomori [17]

Answer:

-2m/s

Explanation:

3 0
2 years ago
What type of waves moves energy forward, but the source moves up and down?
stich3 [128]
I'm pretty sure its transverse waves 
4 0
3 years ago
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