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yulyashka [42]
3 years ago
14

A weightlifter lifted 800 Newtons to a height of 2.5 meters. What is the power output if this was

Physics
1 answer:
stiv31 [10]3 years ago
5 0

The power required is 1.6 kW.

Answer:

Explanation:

Power is defined as the amount of work done on any object for a given time interval. In other words, power is the amount of force required to move an object in a given period of time.

Power = Work done / time taken for that work done.

Here the force is given as 800 N and the displacement is given as 2.5 m, while the time required for the displacement is given as 1.22 seconds.

So the power will be ratio of the  product of force acting on the weightlifter, displacement of the weight to the time taken for that displacement.

Power = (800×2.5)/1.22 =1639 W

So the power required is 1.6 kW.

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Answer:

12 m/s

Explanation:

a = v² / r

78 m/s² = v² / 2.0 m

v = 12.49 m/s

Rounding to two significant figures, the speed is 12 m/s.

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If 12 coulombs of electric charge pass a point in 4.0
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Help!! I’ll give brainliest! Match the changes in sound wave properties with their effects on an observer.
aivan3 [116]
The answers are:
A:1
B:2
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In short, they are already arranged. 

<em>Pitch </em><em />is defined as the sensation of a frequency. A high frequency corresponds to a high pitch. Low frequency corresponds to low pitch. So it is right to assume that rising frequency will cause a rising pitch. 

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5 0
3 years ago
A point charge q = +4.50 nC moves through a potential difference ΔV = Vf − Vi = +27.0 V. What is the change in the electric pote
olganol [36]

Change in electric potential energy: 121.5 nJ

Explanation:

For a charged particle moving in an electric field, the change in electric potential energy of the particle is given by

\Delta U = q \Delta V

where:

q is the charge of the particle

\Delta V is the potential difference between the initial and final position of the particle

For the point charge in this problem, we have:

q=+4.50 nC is the charge

\Delta V=+27.0 V is the potential difference

Therefore, the change in electric potential energy is

\Delta U=(+4.50)(+27.0)=121.5 nJ

Learn more about electric fields:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

6 0
3 years ago
PHYSICS can somebody please answer this
tankabanditka [31]
Yes the answer is recoiled of the Gaian and the hash of attorney then the distance must be bábale of the original number
8 0
3 years ago
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