1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Stells [14]
2 years ago
7

If he were able to maintain this constant rate of acceleration, what would have been his speed as he finished the race?

Physics
1 answer:
Law Incorporation [45]2 years ago
5 0

a) 4.8 m/s² his average acceleration during the first 2.5 s

b) 15 m distance he cover during the first 2.5 seconds.

c) 31 m/s his speed as he finished the race.

<h3>(a) How to calculate the Average Acceleration ?</h3>

Average acceleration is calculated by using Newtons first law of motion

v = u + at

where

u is initial velocity

v is final velocity

a is constant acceleration

t is time

Given u = 0m/s , v = 12 m/s and t = 2.5 sec

Therefore average acceleration is given by

a=\frac{v}{t}

a=\frac{12}{2.5}

a = 4.8 m/sec²

b) Here we will use newtons second law of motion

s=ut+\frac{1}{2}at^{2}

On substituting value we get

s = 15m

c) Here we will use newtons third law of motion

v² = u² + 2as

Here u = 0 , a = 4.8 m/s² and s = 100 m

Therefore

v² = 960

v = 31 m/s

Disclaimer: the question was given incomplete in the portal. Here is the complete question.

Question: Usain Bolt's 100m sprint Runner set the world record for the100 meter sprint during the 2009World Championships in Berlin with a time of 9.58 s, reaching a top speed of 12 m/s in about 2.5 s.

a. What was his average acceleration during the first 2.5 s?

b. What distance did he cover during the first 2.5 seconds, assuming his acceleration was constant?

c. If he were able to maintain this constant rate of acceleration, what would have been his speed as he finished the race?

Learn more about Newtons law of motion here:

brainly.com/question/12525794

#SPJ4

You might be interested in
A weightlifter lifts a 250-kg mass 0.5 meters above his head, how much PEg does the mass have (Note: g=9.8 m/s2)? Round your ans
Anna71 [15]
The Gravitationa potential energy of the mass (PEG) is given by:
U=mgh
where
m is the mass
g is the gravitational acceleration
h is the heigth of the mass above the reference level (the ground)

In this problem, m=250 kg and h=0.5 m, therefore the gravitational potential energy of the mass is:
U=mgh=(250 kg)(9.8 m/s^2)(0.5 m)=1225 J
6 0
3 years ago
Read 2 more answers
___________ are over 500 million years old and have been developing their unique system all that time.
zhannawk [14.2K]

Answer:

C

Explanation:

3 0
3 years ago
Read 2 more answers
Where are the nucleus and the electrons located in this atom
levacccp [35]
In the middle the nucleus is thr brain of it and the electrons spin around the whole atom
5 0
3 years ago
What is the maximum value of the magnetic field at a<br> distance2.5m from a 100-W light bulb?
MA_775_DIABLO [31]

To solve this problem we will apply the concepts related to the intensity included as the power transferred per unit area, where the area is the perpendicular plane in the direction of energy propagation.

Since the propagation occurs in an area of spherical figure we will have to

I = \frac{P}{A}

I = \frac{P}{4\pi r^2}

Replacing with the given power of the Bulb of 100W and the radius of 2.5m we have that

I = \frac{100}{4\pi (2.5)^2}

I = 1.2738W/m^2

The relation between intensity I and E_{max}

I = \frac{E_max^2}{2\mu_0 c}

Here,

\mu_0 = Permeability constant

c = Speed of light

Rearranging for the Maximum Energy and substituting we have then,

E_{max}^2 = 2I\mu_0 c

E_{max}=\sqrt{2I\mu_0 c }

E_{max} = 2(1.2738)(4\pi*10^{-7})(3*10^8)

E_{max} = 30.982 V/m

Finally the maximum magnetic field is given as the change in the Energy per light speed, that is,

B_{max} = \frac{E_{max}}{c}

B_{max} = \frac{30.982 V /m}{3*10^8}

B_{max} = 1.03275 *10{-7} T

Therefore the maximum value of the magnetic field is B_{max} = 1.03275 *10{-7} T

3 0
3 years ago
A 1kg dictionary is resting on a table that is 1.5m high. How much potential energy
melamori03 [73]

Answer:

Potential energy = 14.7 Joules.

Explanation:

Given the following data;

Mass, m = 1kg

Height, h = 1.5m

We know that acceleration due to gravity is equal to 9.8m/s²

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

P.E = mgh

Where, P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

P.E = mgh

Substituting into the equation, we have;

P.E = 1*9.8*1.5

P.E = 14.7 Joules.

6 0
3 years ago
Other questions:
  • The following diagram represents a cart with an initial velocity of 1.0 m/s sliding along a frictionless track from point A:
    9·2 answers
  • If a wave were nine feet high, how much would the amplitude be?
    6·2 answers
  • Calculate the pressure on the bottom of a swimming pool 3. 5 m deep. How does the pressure compare with atmospheric pressure, 10
    11·1 answer
  • What two controls on a car cause a change in speed? What control causes only a change in velocity
    7·1 answer
  • With a magnetic field strength of 1.41 tesla, all of the protons in organic compounds will resonate over a narrow range of frequ
    11·1 answer
  • Which of the following statements is a true statement about the use of nuclear energy as an alternative energy source?
    11·1 answer
  • The arm of a crane at a construction site is 17.0 m long, and it makes an angle of 11.6 ◦ with the horizontal. Assume that the m
    7·1 answer
  • I need help with these questions thank u
    15·1 answer
  • A flat (unbanked) curve on a highway has a radius of 220.0 m. A car rounds the curve at a speed of 25.0 m/s.
    11·1 answer
  • Why did a coke ice cube melt faster than a normal ice cube?
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!