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solong [7]
2 years ago
7

A person walks due south from point A for 500 yards and then due west for 300 yards, arriving at point B. Answer the following q

uestions using complete sentences. 2 points for each correct answer and 2 points for each correct explanation. i. What is the person's displacement from the starting point
Physics
1 answer:
Pepsi [2]2 years ago
5 0

The total displacement of the person walking from point A to point B is 300 yards.

As shown in the figure we can conclude that the required method to calculate the total displacement is the Pythagoras theorem.

<h3>Pythagoras theorem in brief :</h3>

According to the Pythagorean Theorem, the square that represents the hypotenuse, or side of a right triangle that faces the right angle, is equal to the total of the squares on the triangle's legs.(or, in popular algebraic notation, a^2 + b^2 = c^2).

<h3>Calculation: </h3>

Let,

a = 500

b=  300

Hence by using Pythagoras' theorem

Total displacement of the person = \sqrt{500^{2}  + 300^{2} } = \sqrt{900000} = 300

Thus the total displacement of the person from starting point is 300 yards.

Learn more about the displacement examples here:

brainly.com/question/11188852

#SPJ4

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Answer:

270 m

Explanation:

Given:

v₀ = 63 m/s

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6 0
3 years ago
In an engine, an almost ideal gas is compressed adiabatically to half its volume. In doing so, 1850 J of work is done on the gas
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Since it is adiabatic compression of the gas so heat transfer to the gas is zero.

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So from equation (1)

⇒ Δ U = - W ----------------- (2)

⇒ W = - 1850 J (Given)

⇒ Δ U = - (- 1850)

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6 0
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A car travels in a straight line for 5 h at a constant speed of 72 km/h. What is it’s acceleration
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Answer:

a \approx \: 0.001 \: m {s}^{ - 2}

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initial \:  velocity \:  (u) = 0 \\  \\ Final  \: Velocity \:  (v) = 72 km /h   \\  \\ Time \:  (t) = 5 \:  hours \\  \\ Acceleration \:  (a) =?  \\  \\  \because \: a =  \frac{v - u}{t}  \\  \\  \therefore \: a =  \frac{72 - 0}{5}  \\  \\ a =  \frac{72}{5}  \\  \\ a = 14.5 \: km {h}^{ - 2}  \\  \\ a =  \frac{14.5 \times 1000}{3600\times 3600} \: m {s}^{ - 2}   \\  \\ a = 0.00111882716 \\  \\ a \approx \: 0.001 \: m {s}^{ - 2}

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