Explanation:
It is given that,
Density of asteroid,
Mass of asteroid,
We need to find the diameter of the asteroid. The formula of density is given by:
V is the volume of spherical shaped asteroid,
r = 2441311.12 m
Diameter = 2 × radius
d = 4882622.24 m
or
Hence, this is the required solution.
Answer:
Amplitude, A = 0.049 meters
Explanation:
Given that,
A harmonic wave travels in the positive x direction at 6 m/s along a taught string. A fixed point on the string oscillates as a function of time according to the equation :
.......(1)
The general equation of a wave is given by :
.......(2)
A is amplitude of wave
On comparing equation (1) and (2) we get :
A = 0.049 meters
So, the amplitude of the wave is 0.049 meters.
Answer:
μ = 0.66, therefore if it compiesy with the regulations
Explanation:
Let's solve this exercise in part, let's start by finding with kinematics the acceleration of man
y = v₀ t + ½ a t²
as it starts from rest the initial velocity is zero
y = ½ a t²
a =
a =\frac{2 \ 4.38}{1.21^2}
a = 6.46 m / s²
Now let's use Newton's second law,
Axis y
N- W = 0
N = W
N = m g
X axis
on this axis the man exerts a backward force and by the law of action and reaction the floor exerts a forward force of the same magnitude, this forward force is the friction force.
fr = m a
the friction force has an expression
fr = my N
let's substitute
μ mg = m a
μ = a / g
let's calculate
μ = 6.46 / 9.8
μ = 0.66
therefore if you comply with the regulations
Answer:
Explanation:
To estimate the focal length of a convex lens follow the following steps.
1. take a convex lens.
2. Stand near a window which is just opposite to a wall.
3. Look at a tree which is far away from the window by the convex lens.
4. focus the image of the tree on the wall which is opposite to the window.
5. You wll observe that by changing the position of convex lens a sharp and inverted and small image is seen on the wall.
5. Now measure the distance between the lens and the wall.
7. This distance is the rough focal length of the convex lens.