The answer to the question is
<span>PE = W = 1/2 (kx^2)
16.2 = </span>1/2 (k(0.30)^2)
k = 360 J/m^2
True the elements are ordered in the atomic number
Answer:
Buttery popcorn contained in a large 1 liter bowl has a mass of about 50 mg and about 650 calories.
Explanation:
Liter is the most appropriate unit to measure a bowl. Usually 1 liter of liquid has a mass of 1000 gram. Since popcorn is something lightweight and only a few can fill the bowl quickly so 50 mg makes perfect sense with 1 liter of bowl and 650 calories in buttery popcorn.
Answer:
(a) 6650246.305 N/C
(b) 24150268.34 N/C
(c) 6408227.848 N/C
(d) 665024.6305 N/C
Explanation:
Given:
Radius of the ring (r) = 10.0 cm = 0.10 m [1 cm = 0.01 m]
Total charge of the ring (Q) = 75.0 μC =
[1 μC = 10⁻⁶ C]
Electric field on the axis of the ring of radius 'r' at a distance of 'x' from the center of the ring is given as:
![E_x=\dfrac{kQx}{(x^2+r^2)^\frac{3}{2}}](https://tex.z-dn.net/?f=E_x%3D%5Cdfrac%7BkQx%7D%7B%28x%5E2%2Br%5E2%29%5E%5Cfrac%7B3%7D%7B2%7D%7D)
Plug in the given values for each point and solve.
(a)
Given:
, ![r=0.01\ m, a=1.00\ cm=0.01\ m,k=9\times 10^{9}\ Nm^2/C^2](https://tex.z-dn.net/?f=r%3D0.01%5C%20m%2C%20a%3D1.00%5C%20cm%3D0.01%5C%20m%2Ck%3D9%5Ctimes%2010%5E%7B9%7D%5C%20Nm%5E2%2FC%5E2)
Electric field is given as:
![E_x=\dfrac{(9\times 10^{9})(75\times 10^{-6})(0.01)}{((0.01)^2+(0.1)^2)^\frac{3}{2}}\\\\E_x=\dfrac{6750}{1.015\times 10^{-3}}\\\\E_x=6650246. 305\ N/C](https://tex.z-dn.net/?f=E_x%3D%5Cdfrac%7B%289%5Ctimes%2010%5E%7B9%7D%29%2875%5Ctimes%2010%5E%7B-6%7D%29%280.01%29%7D%7B%28%280.01%29%5E2%2B%280.1%29%5E2%29%5E%5Cfrac%7B3%7D%7B2%7D%7D%5C%5C%5C%5CE_x%3D%5Cdfrac%7B6750%7D%7B1.015%5Ctimes%2010%5E%7B-3%7D%7D%5C%5C%5C%5CE_x%3D6650246.%20305%5C%20N%2FC)
(b)
Given:
, ![r=0.01\ m, a=5.00\ cm=0.05\ m,k=9\times 10^{9}\ Nm^2/C^2](https://tex.z-dn.net/?f=r%3D0.01%5C%20m%2C%20a%3D5.00%5C%20cm%3D0.05%5C%20m%2Ck%3D9%5Ctimes%2010%5E%7B9%7D%5C%20Nm%5E2%2FC%5E2)
Electric field is given as:
![E_x=\dfrac{(9\times 10^{9})(75\times 10^{-6})(0.05)}{((0.05)^2+(0.1)^2)^\frac{3}{2}}\\\\E_x=\dfrac{33750}{1.3975\times 10^{-3}}\\\\E_x=24150268.34\ N/C](https://tex.z-dn.net/?f=E_x%3D%5Cdfrac%7B%289%5Ctimes%2010%5E%7B9%7D%29%2875%5Ctimes%2010%5E%7B-6%7D%29%280.05%29%7D%7B%28%280.05%29%5E2%2B%280.1%29%5E2%29%5E%5Cfrac%7B3%7D%7B2%7D%7D%5C%5C%5C%5CE_x%3D%5Cdfrac%7B33750%7D%7B1.3975%5Ctimes%2010%5E%7B-3%7D%7D%5C%5C%5C%5CE_x%3D24150268.34%5C%20N%2FC)
(c)
Given:
, ![r=0.01\ m, a=30.0\ cm=0.30\ m,k=9\times 10^{9}\ Nm^2/C^2](https://tex.z-dn.net/?f=r%3D0.01%5C%20m%2C%20a%3D30.0%5C%20cm%3D0.30%5C%20m%2Ck%3D9%5Ctimes%2010%5E%7B9%7D%5C%20Nm%5E2%2FC%5E2)
Electric field is given as:
![E_x=\dfrac{(9\times 10^{9})(75\times 10^{-6})(0.30)}{((0.30)^2+(0.1)^2)^\frac{3}{2}}\\\\E_x=\dfrac{202500}{0.0316}\\\\E_x=6408227.848\ N/C](https://tex.z-dn.net/?f=E_x%3D%5Cdfrac%7B%289%5Ctimes%2010%5E%7B9%7D%29%2875%5Ctimes%2010%5E%7B-6%7D%29%280.30%29%7D%7B%28%280.30%29%5E2%2B%280.1%29%5E2%29%5E%5Cfrac%7B3%7D%7B2%7D%7D%5C%5C%5C%5CE_x%3D%5Cdfrac%7B202500%7D%7B0.0316%7D%5C%5C%5C%5CE_x%3D6408227.848%5C%20N%2FC)
(d)
Given:
, ![r=0.01\ m, a=100\ cm=1\ m,k=9\times 10^{9}\ Nm^2/C^2](https://tex.z-dn.net/?f=r%3D0.01%5C%20m%2C%20a%3D100%5C%20cm%3D1%5C%20m%2Ck%3D9%5Ctimes%2010%5E%7B9%7D%5C%20Nm%5E2%2FC%5E2)
Electric field is given as: