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blsea [12.9K]
2 years ago
5

a spring is hanging down from the ceiling, and an object of mass m is attached to the free end. the object is pulled down, there

by stretching the spring, and then released. the object oscillates up and down, and the time t required for one complete up-and-down oscillation is given by the equation t
Physics
1 answer:
Maurinko [17]2 years ago
7 0

The dimension of K is M/ T^2

according to the question T=2π square root ofm/k here 2 pi is constant so  

T= root of m /k and root of k = root of m/ T now by squaring on both the sides we get the answer k= M/ T^2

complete question :

A spring is hanging down from the ceiling, and an object of mass m is attached to the free end. The object is pulled down, thereby stretching the spring, and then released. The object oscillates up and down, and the time T required for one complete up-and-down oscillation is given by the equation T=√2πm/k, where k is known as the spring constant. What must be the dimension of k for this equation to be dimensionally correct?

To learn more about dimension:

brainly.com/question/13314350

#SPJ4

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5 0
3 years ago
You have been hired to design a spring-launched roller coaster that will carry two passengers per car. The car goes up a 12-m-hi
Vlada [557]

Answer:

Vmax=11.53 m/s

Explanation:

from conservation of energy

      E_A} =E_{B}

     Spring potential energy =potential energy due to elevation

   0.5*k*x²= mg(h_{B}-h_{A} )=mgh

   0.5*k*2.3²= 430*9.81*6

         k=9568.92 N/m

For safety reason

                                 k"=1.13 *k= 1.13*9568.92

                                    k"=10812.88 N/m

agsin from conservation of energy

      E_A} =E_{C}

    spring potential energy=change in kinetic energy

   0.5*k"*x²=0.5*m*V_{max}^{2}

      10812.88 *2.3²=430*V_{max}^{2}

           V_{max}=11.53 m/s

5 0
4 years ago
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