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blsea [12.9K]
2 years ago
5

a spring is hanging down from the ceiling, and an object of mass m is attached to the free end. the object is pulled down, there

by stretching the spring, and then released. the object oscillates up and down, and the time t required for one complete up-and-down oscillation is given by the equation t
Physics
1 answer:
Maurinko [17]2 years ago
7 0

The dimension of K is M/ T^2

according to the question T=2π square root ofm/k here 2 pi is constant so  

T= root of m /k and root of k = root of m/ T now by squaring on both the sides we get the answer k= M/ T^2

complete question :

A spring is hanging down from the ceiling, and an object of mass m is attached to the free end. The object is pulled down, thereby stretching the spring, and then released. The object oscillates up and down, and the time T required for one complete up-and-down oscillation is given by the equation T=√2πm/k, where k is known as the spring constant. What must be the dimension of k for this equation to be dimensionally correct?

To learn more about dimension:

brainly.com/question/13314350

#SPJ4

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Mass (kg) 4.0
densk [106]

Answer:

25 m/s

Explanation:

First of all, we can find the acceleration the object by using Newton's second law of motion:

F=ma

where

F = 20.0 N is the net force applied on the object

m = 4.0 kg is the mass of the object

a is its acceleration

Solving for a, we find

a=\frac{F}{m}=\frac{20}{4}=5.0 m/s^2

Now we know that the motion of the object is a uniformly accelerated motion, so we can find its final velocity by using the following suvat equation:

v=u+at

where

v is the final velocity

u = 0 is the initial velocity

a=5.0 m/s^2 is the acceleration

t = 5 s is the time

By substituting,

v=0+(5.0)(5)=25 m/s

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