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RSB [31]
4 years ago
7

Which pair of formulas represents the same compound? ch3ch2cho; ch3ch2cooh ch3coh(ch32; (ch3 3coh c2h5oh; ch3och3 (ch32co; ch3oc

h3?
Chemistry
2 answers:
DiKsa [7]4 years ago
8 0
CH3COH(CH3)2; (CH3)3COH is the answer. Please let me know if this helps.
HACTEHA [7]4 years ago
8 0

Answer: The correct answers are CH_3COH(CH_3)_2;(CH_3)_3COH and C_2H_5OH;CH_3OCH_3

Explanation:

The formulas having same compound will have same number of individual atoms.

From the given options:

  • <u>Option 1:</u> CH_3CH_2CHO;CH_3CH_2COOH

In compound 1:

Number of carbon atoms = 3

Number of hydrogen atoms = 6

Number of oxygen atoms = 1

In compound 2:

Number of carbon atoms = 3

Number of hydrogen atoms = 6

Number of oxygen atoms = 2

As, number of oxygen atoms in both the compounds are not same. Thus, these two do not represent same compounds.

  • <u>Option 2:</u> CH_3COH(CH_3)_2;(CH_3)_3COH

In compound 1:

Number of carbon atoms = 4

Number of hydrogen atoms = 10

Number of oxygen atoms = 1

In compound 2:

Number of carbon atoms = 4

Number of hydrogen atoms = 10

Number of oxygen atoms = 1

Here, all the atoms of every element is same. Thus, these two compounds represent same compound.

  • <u>Option 3:</u> C_2H_5OH;CH_3OCH_3

In compound 1:

Number of carbon atoms = 2

Number of hydrogen atoms = 6

Number of oxygen atoms = 1

In compound 2:

Number of carbon atoms = 2

Number of hydrogen atoms = 6

Number of oxygen atoms = 1

Here, all the atoms of every element is same. Thus, these two compounds represent same compound.

  • <u>Option 4:</u> (CH_3)_2CO;CH_3OCH_3

In compound 1:

Number of carbon atoms = 3

Number of hydrogen atoms = 6

Number of oxygen atoms = 1

In compound 2:

Number of carbon atoms = 2

Number of hydrogen atoms = 6

Number of oxygen atoms = 1

As, number of carbon atoms in both the compounds are not same. Thus, these two do not represent same compounds.

Hence, the pairs which represent same compounds are CH_3COH(CH_3)_2;(CH_3)_3COH and C_2H_5OH;CH_3OCH_3

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Given the following data:N2(g) + O2(g)→ 2NO(g), ΔH=+180.7kJ2NO(g) + O2(g)→ 2NO2(g), ΔH=−113.1kJ2N2O(g) → 2N2(g) + O2(g), ΔH=−163
statuscvo [17]

Answer:

ΔH = +155.6 kJ

Explanation:

The Hess' Law states that the enthalpy of the overall reaction is the sum of the enthalpy of the step reactions. To do the addition of the reaction, we first must reorganize them, to disappear with the intermediaries (substances that are not presented in the overall reaction).

If the reaction is inverted, the signal of the enthalpy changes, and if its multiplied by a constant, the enthalpy must be multiplied by the same constant. Thus:

N₂(g) + O₂(g) → 2NO(g) ΔH = +180.7 kJ

2NO(g) + O₂(g) → 2NO₂(g) ΔH = -113.1 kJ

2N₂O(g) → 2N₂(g) + O₂(g) ΔH = -163.2 kJ

The intermediares are N₂ and O₂, thus, reorganizing the reactions:

N₂(g) + O₂(g) → 2NO(g) ΔH = +180.7 kJ

NO₂(g) → NO(g) + (1/2)O₂(g) ΔH = +56.55 kJ (inverted and multiplied by 1/2)

N₂O(g) → N₂(g) + (1/2)O₂(g) ΔH = -81.6 kJ (multiplied by 1/2)

------------------------------------------------------------------------------------

N₂O(g) + NO₂(g) → 3NO(g)

ΔH = +180.7 + 56.55 - 81.6

ΔH = +155.6 kJ

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Gekata [30.6K]

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bagirrra123 [75]

The noble gas is Xenon and its molar mass is 131 g/mol.

<h3>What is the molar mass of the noble gas?</h3>

The molar mass of the noble gas is determined as follows;

Let molar mass of unknown gas be M, and mass of gas be m

Density of the noble gas, ρ = 5.8 g/dm³

density = m/V

At STP;

  • temperature, T = 273.15 K
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From ideal gas equation:

PV = nRT

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PV = mRT/M

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M =  0.0821 * 273.15 * 5.84/1

Molar mass of the noble gas = 131 g/mol

The noble gas is Xenon which has molar mass approximately equal to 131 g/mol.

Learn more about molar mass at: brainly.com/question/837939

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