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RSB [31]
4 years ago
7

Which pair of formulas represents the same compound? ch3ch2cho; ch3ch2cooh ch3coh(ch32; (ch3 3coh c2h5oh; ch3och3 (ch32co; ch3oc

h3?
Chemistry
2 answers:
DiKsa [7]4 years ago
8 0
CH3COH(CH3)2; (CH3)3COH is the answer. Please let me know if this helps.
HACTEHA [7]4 years ago
8 0

Answer: The correct answers are CH_3COH(CH_3)_2;(CH_3)_3COH and C_2H_5OH;CH_3OCH_3

Explanation:

The formulas having same compound will have same number of individual atoms.

From the given options:

  • <u>Option 1:</u> CH_3CH_2CHO;CH_3CH_2COOH

In compound 1:

Number of carbon atoms = 3

Number of hydrogen atoms = 6

Number of oxygen atoms = 1

In compound 2:

Number of carbon atoms = 3

Number of hydrogen atoms = 6

Number of oxygen atoms = 2

As, number of oxygen atoms in both the compounds are not same. Thus, these two do not represent same compounds.

  • <u>Option 2:</u> CH_3COH(CH_3)_2;(CH_3)_3COH

In compound 1:

Number of carbon atoms = 4

Number of hydrogen atoms = 10

Number of oxygen atoms = 1

In compound 2:

Number of carbon atoms = 4

Number of hydrogen atoms = 10

Number of oxygen atoms = 1

Here, all the atoms of every element is same. Thus, these two compounds represent same compound.

  • <u>Option 3:</u> C_2H_5OH;CH_3OCH_3

In compound 1:

Number of carbon atoms = 2

Number of hydrogen atoms = 6

Number of oxygen atoms = 1

In compound 2:

Number of carbon atoms = 2

Number of hydrogen atoms = 6

Number of oxygen atoms = 1

Here, all the atoms of every element is same. Thus, these two compounds represent same compound.

  • <u>Option 4:</u> (CH_3)_2CO;CH_3OCH_3

In compound 1:

Number of carbon atoms = 3

Number of hydrogen atoms = 6

Number of oxygen atoms = 1

In compound 2:

Number of carbon atoms = 2

Number of hydrogen atoms = 6

Number of oxygen atoms = 1

As, number of carbon atoms in both the compounds are not same. Thus, these two do not represent same compounds.

Hence, the pairs which represent same compounds are CH_3COH(CH_3)_2;(CH_3)_3COH and C_2H_5OH;CH_3OCH_3

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grigory [225]

Answer:

Here you can use the Clausis Clayperon equation: ln P1/P2=-Ea/R-(1/T1 - 1/T2)

where P1 is the pressure at standard condition: 760 mm Hg

P2 is the variable we need to solve

Ea is the activation energy, which in this case is delta H vaporisation: 56.9 kJ/mol

R is the gas constant 8.314 J/mol or 8.314 J/mol /1000 to convert to kJ

T1 is the normal boiling point 356.7 C, but converted to Kelvin: 629.85K

T2 is room temperature 25 C, but converted to Kelvin: 298.15 K

Once you plug everything in, you should get 4.29*10^-3 mmHg

Explanation:

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77julia77 [94]

Answer:

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What volume of stock solution and water must you add to prepare 36.25ml of a 1.25M solution
Serjik [45]

Given :

Number of moles , n = 36.25 mol .

Molarity , M = 1.25 M .

To Find :

The volume of water required .

Solution :

Moarity is given by :

M=\dfrac{n}{V}

So , V=\dfrac{n}{M}

Here , n is number of moles and M is molarity .

Putting all values in above equation , we get :

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Which is the balanced chemical equation showing hydrogen peroxide (H2O2) decomposing into hydrogen (H2) and oxygen (O2)? Multipl
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Answer: H_2O_2\rightarrow H_2+O_2

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

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