Answer:
Q = 5036.9 calories
Explanation:
Given that,
Mass, m = 167.9 g
The temperature raises from 25°C to 55°C.
The specific heat of water,c = 4.184 J/g °C
We need to find the heat added to water. We know that,

or
Q = 5036.9 calories
So, 5036.9 calories of heat is added.
Ooo im taking chem this semester and just around this subject,
water is neutral and <span>H2CO3cant act as b-l base soo </span>the answer is HCIO4(aq)