Pb + Mg(NO₃)₂ → Pb(NO₃)₂ + Mg
This reaction would NOT occur because Pb is less reactive than Mg and as such Pb cannot displace the Mg in order for the reaction to occur under normal conditions.
Mg + Fe(NO₃)₂ → Fe + Mg(NO₃)₂
This reaction would occur. This is because Mg is more reactive than Fe and as such can displace it in the reaction, thus allowing the reaction to occur under normal conditions.
Cu + Mg(NO₃)₂ → Cu(NO₃)₂ + Mg
This reaction would NOT occur. Mg is more reactive than Cu, and as such copper cannot displace magnesium in order for the reaction to occur under normal conditions.
Answer:
Thermocline separate these two layers.
Explanation:
Ocean consist of three major layers on the basis of temperature.
1. Upper layer
2. Deep layer
3. Thermocline
Upper layer:
The first layer is called upper layer which is present on the surface and directly expose to the sun. The sun heat up this upper layer easily and warm it.
Deep layer
The deep layer is present below the thermocline. It is present in deep where sunlight can not approach to it and its temperature remain low.
Thermocline
It is the middle layer, present between the upper and deep layer. It separated the upper layer from deep layer. Its upper portion is warmer while lower is colder.
The answr to your question is 325.15
Answer:
See Explanation
Explanation:
Because you have to get through the d-block electron configurations for the rest of the p-block elements which is a hassle to do. You need to know how to account for electron stability, from which subshell to remove electrons, etc. because it is all weird for d-block.
The standard enthalpy of formation (Δ
) is a measure of the energy released or consumed when one mole of a substance is created under standard conditions from its pure elements.
Standard enthalpies (Δ) of formation for given reaction is 978.3 kJ
<h3>
What is Standard enthalpies of formation?</h3>
The standard enthalpy of formation is defined as the enthalpy change when one mole of a substance in the standard state (1 atm of pressure and 298.15 K) is formed from its pure elements under the same conditions.
Given reaction ;
To Find : Δ
Δ = ∑np Δ (products) – ∑np Δ (reactants)
Δ = [1(Δ 
) + 4(Δ 
)] – [1(Δ 
) + 4(Δ 
)]
Δ = [1(0) + 4(-241.8)] – [1(+9.16) + 4(0)]
Δ = [4(-241.8)] – [1(+9.16)] = 978.3 kJ
Learn more about Enthalpy here ;
brainly.com/question/16720480
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