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Misha Larkins [42]
2 years ago
12

Which element has the electron configuration [xe] 6s2 4f14 5d10 6p2? a. gold (atomic number 79) b. mercury (atomic number 80) c.

lead (atomic number 82) d. potassium (atomic number 19) e. copper (atomic number 29)
Chemistry
1 answer:
denis-greek [22]2 years ago
4 0

Lead (Pb) has the electron configuration [xe] 6s2 4f14 5d10 6p2.

<h3><u>What is electronic configuration ?</u></h3>

A neutral element's total number of electrons is represented by its electronic configuration. To get the total number of electrons in an atom, we sum all the superscripts.

As the last electron enters the p orbital, the provided element is a p block element. Xenon, a noble gas with 54 electrons, is the closest.

According to Afbau's rule, the electrons are filled in the sequence of increasing energies, and the electronic configuration in terms of the noble gs configuration is as follows:

Total electrons = 54 + 2 + 14 + 10 + 2 = 82

Lead is the element with the symbol whose atomic number is 82 since it contains 82 electrons.

To view more about configuration, refer to:

brainly.com/question/14190064

#SPJ4

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Given these reactions, where X represents a generic metal or metalloid 1) H2(g)+12O2(g)⟶H2O(g)ΔH1=−241.8 kJ 1) H2(g)+12O2(g)⟶H2O
Bond [772]

Answer:

ΔH = -793,6 kJ

Explanation:

It is possible to obtain ΔH of this reaction using Hess's law that says you can sum the half-reactions ΔH to obtain the ΔH of the global reaction:

If half-reactions are:

1) H₂(g) + ¹/₂O₂(g) ⟶ H₂O(g) ΔH₁ = −241.8 kJ

2) X(s) + 2Cl₂(g) ⟶ XCl₄(s) ΔH₂ = +356.9 kJ  

3) ¹/₂H₂(g) + ¹/₂Cl₂(g) ⟶ HCl(g) ΔH₃ = −92.3 kJ

4) X(s) + O₂(g) ⟶ XO₂(s) ΔH₄ = −639.1 kJ

5) H₂O(g) ⟶ H₂O(l) ΔH₅ = −44.0 kJ

The sum of (4) + 4×(3) - (2) - 2×(1) - 2×(5) is:

(4) X(s) + O₂(g) ⟶ XO₂(s) ΔH = −639.1 kJ

+4×(3) 2H₂(g) + 2Cl₂(g) ⟶ 4HCl(g) ΔH = −369,2 kJ

-(2) XCl₄(s) ⟶ X(s) + 2Cl₂(g) ΔH = -356,9 kJ

-2×(1) 2H₂O(g) ⟶ 2H₂(g) + O₂(g) ΔH = +483,6 kJ

-2×(5) 2H₂O(l) ⟶ 2H₂O(g) ΔH = +88.0 kJ

= <em>XCl₄(s) + 2H₂O(l) ⟶ XO₂(s) + 4HCl(g)</em>

Where ΔH is:

ΔH = -639,1 kJ -369,2 kJ -356,9 kJ +483,6 kJ +88,0 kJ

<em>ΔH = -793,6 kJ</em>

I hope it helps!

5 0
3 years ago
According to the article, puberty indicates the beginning of adolescence. How does nutrition influence the start of adolescence?
Arisa [49]

Answer:

<h3>  adolescence begins according to your diet</h3>

Explanation                                                                                          <em>unhealthy diet</em>  brings about early or late commence  of adolescence especially  in girls                                                                                                                          

6 0
2 years ago
Why is only one diastereomer formed in this reaction? Relate your answer to the mechanism you drew. b) If you used cis-stilbene
crimeas [40]

Answer:

1. Diastereomers have different physical properties (unlike most aspects of enantiomers) and often different chemical reactivity. ... Many conformational isomers are diastereomers as well. Diastereoselectivity is the preference for the formation of one or more than one diastereomer over the other in an organic reaction.

2. The result is a trans dibromide, as shown in the equation below

Explanation:

Diastereomers (sometimes called diastereoisomers) are a type of a stereoisomer.[1] Diasteoreomers are defined as non-mirror image non-identical stereoisomers. Hence, they occur when two or more stereoisomers of a compound have different configurations at one or more (but not all) of the equivalent (related) stereocenters and are not mirror images of each other.[2] When two diastereoisomers differ from each other at only one stereocenter they are epimers. Each stereocenter gives rise to two different configurations and thus typically increases the number of stereoisomers by a factor of two.

2. the addition of bromine to the trans and

cis isomers of 1,2-diphenylethene, more commonly known as trans- and cis-stilbene.

H

H

H H

trans-stilbene cis-stilbene

m.p. 122-124°C b.p. 82-84°C

density 0.970 g/mL density 1.011 g/mL

M.W. 180.25 g/mol M.W. 180.25 g/mol

In both cases, the nucleophilic double bond undergoes an electrophilic addition reaction

by the bromine reagent which proceeds via a cyclic bromonium ion. The addition of

bromine begins at one side of the double bond (either side is equally likely, but only one

option is drawn) and is followed by attack of bromide ion on the bromonium ion (again,

attack could occur at either carbon since the ion is symmetric, but only one option is

drawn). The result is a trans dibromide, as shown in the equation below:

Since the cis and trans isomers of stilbene have different geometries, it follows

that upon reaction with bromine they give rise to stereoisomeric bromonium ions and,

eventually, products that differ only by their stereochemistry.

4 0
4 years ago
A sample gas initially occupies 3.35
Strike441 [17]
After i don’t get it
7 0
3 years ago
How many grams of NaHCO3are in 3.75 x 10 ^-3 moles of NaHCO3<br><br> PLS HELP DUE TODAY
hodyreva [135]

Answer: m= 3.15x10-3 g NaHCO3

Explanation: To find the mass of NaHCO3 we will use the relationship between moles and molar mass. The molar mass of NaHCO3 is 84 g.

3.75x10-5 moles NaHCO3 x 84 g NaHCO3 / 1 mole NaHCO3

= 3.15x10-3 g NaHCO3

3 0
3 years ago
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