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Misha Larkins [42]
2 years ago
12

Which element has the electron configuration [xe] 6s2 4f14 5d10 6p2? a. gold (atomic number 79) b. mercury (atomic number 80) c.

lead (atomic number 82) d. potassium (atomic number 19) e. copper (atomic number 29)
Chemistry
1 answer:
denis-greek [22]2 years ago
4 0

Lead (Pb) has the electron configuration [xe] 6s2 4f14 5d10 6p2.

<h3><u>What is electronic configuration ?</u></h3>

A neutral element's total number of electrons is represented by its electronic configuration. To get the total number of electrons in an atom, we sum all the superscripts.

As the last electron enters the p orbital, the provided element is a p block element. Xenon, a noble gas with 54 electrons, is the closest.

According to Afbau's rule, the electrons are filled in the sequence of increasing energies, and the electronic configuration in terms of the noble gs configuration is as follows:

Total electrons = 54 + 2 + 14 + 10 + 2 = 82

Lead is the element with the symbol whose atomic number is 82 since it contains 82 electrons.

To view more about configuration, refer to:

brainly.com/question/14190064

#SPJ4

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A sample of nitric acid contains both H3O ions and NO3 ions. This sample has a pH
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4 0
4 years ago
. A compound contains only C, H, N, and O. It contains 37.0 % C and 42.5% O (both by mass), and there are 2 O atoms for every 1
jasenka [17]

Answer:

C₂₁H₁₅N₉O₁₈

Explanation:

Molecular formula is the ratio of atoms that are present in 1 molecule of the compound. We need to find moles of all atoms to find this ratio.

In a basis of 100, moles of C and O are:

<em>Moles C:</em>

37.0 * (1mol / 12g) = 3.083 moles C

<em>Moles O: </em>

42.5g * (1mol / 16) = 2.656 moles O

Now, to find moles of H, we need determine moles of H2O produced:

0.0310g H2O * (1mol / 18g) = 1.72x10⁻³ moles H2O * 2 = 3.44x10⁻³ moles H

These moles were produced when 0.157g of the compound react. In a basis of 100g:

3.44x10⁻³ moles H * (100g / 0.157g) = 2.194 moles H

In the same way, moles of N are:

0.0230g NH3 * (1mol / 17g) = 1.35x10⁻³ moles H2O

These moles were produced when 0.103g of the compound react. In a basis of 100g:

1.35x10⁻³ moles H * (100g / 0.103g) = 1.313 moles N

Empirical formula is (The simplest whole number ratio of atoms presents in a molecule). Dividing in the low number of moles (Moles N):

C: 3.083 moles C / 1.313 moles N = 2.3

O: 2.656 moles O / 1.313 moles N = 2.0

N: 1.313 moles N / 1.313 moles N = 1

H: 2.194 moles H / 1.313 moles N = 1.67

This ratio times 3 (To have the whole number ratio):

C: 7

O: 6

N: 3

H: 5

The empirical formula is:

C₇H₅N₃O₆

And weighs:

C: 7*(12g/mol)= 84

H: 5 * (1g/mol) = 5

N: 3 * (14g/mol) = 42

O: 6* (16g/mol) = 96

227g/mol

As the molecular mass of the compound is 681g/mol:

681 / 227 = 3

The empirical formula times 3 is the molecular formula, that is:

C₇H₅N₃O₆ × 3

<h3>C₂₁H₁₅N₉O₁₈</h3>

4 0
3 years ago
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