Ask question

Ask question

All categories

3 years ago

7

A cyclist maintains a constant velocity of 6.1 m/s headed away from point A. At some initial time, the cyclist is 242 m from poi

nt A. What will be his displacement from his starting position after 51 s? Answer in units of m.

1 answer:

KengaRu [80]3 years ago

7 0

Answer:

553.1m

Explanation:

When an object moves at constant velocity we can express this movement like V=x/t, where V is the velocity, x is the displacement and t is the time spent on it.

In that way, the expression x=V.t give us the displacement from t=0s until t=51s, but we have to sum the initial distance from the point A.

x=242m +V.t = 242m + (6.1m/s x 51s) = 553.1m

You might be interested in

.2, A car starting from rest has an acceleration of

riadik2000 [5.3K]

Answer: 2.5 m/s and 6.25 m

Explanation:

u = 0

a = 0.5 m/s²

t = 5 s

v = u + at

= 0 + 0.5 × 5

= <u>2.5 m/s</u>

s = ut + 1/2 at²

= 1/2 × 2.5 × 5

=<u> 6.25 m</u>

7 0

3 years ago

A boy uses a force to keep a rock from falling. (He is carrying the rock.) Some forces, like this one, act only when two objects

MArishka [77]

Gravity is a non contact force , jump from a little high place (don't do that :P) , you wont just get stuck in the air you will fall down , this is gravity you dont need any contact

5 0

3 years ago

The graph is the path Beth took on a walk.

PIT_PIT [208]

Answer:

Beth went back toward her origin

Explanation:

Please, see the attached image that represent's Beth's path.

She started her walk 2 meters from the origin (0) and after 6 seconds she headed back to position zero (0) the origin. Notice the second half of the graph as a segment going down, thus reducing her distance from the origin, and getting closer to it.

6 0

3 years ago

Read 2 more answers

In an internal combustion engine, air at atmostpheric

notsponge [240]

Answer:

1302 K or 1029 C

Explanation:

Air at atmospheric pressure has pressure of 1 atm

20 C = 20 + 273 = 293 K

Assume ideal gas, according to the ideal gas law:

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

Where P1, V1 and T1 are the pressure, volume and temperature of the gas before the compression and P2, V2 and T2 are the pressure, volume and temperature of the gas after the compression

$T_2 = T_1\frac{P_2V_2}{P_1V_1}$

Since the gas is compressed to 1/9 of its original volume, V2/V1 = 1/9:

$T_2 = 293\frac{40}{9} = 1302 K$ or 1029 C

8 0

3 years ago

g A hydraulic press has a safety feature which consists of a hydraulic cylinder with a piston at one end and a safety valve at t

nlexa [21]

Answer:

58.32 N

Explanation:

Area of a circle = $\pi$ $r^{2}$

where r is the radius of the circle.

The cylinder has a radius of 0.02 m, its area is;

$A_{1}$ = $\pi$ $r^{2}$

= $\frac{22}{7}$ x $(0.02)^{2}$

= $\frac{22}{7}$ x 0.0004

= 1.2571 x $10^{-3}$

Area of the cylinder is 0.0013 $m^{2}$ .

The safety valve has a radius of 0.0075 m, its area is;

$A_{2}$ = $\pi$ $r^{2}$

= $\frac{22}{7}$ x $(0.0075)^{2}$

= $\frac{22}{7}$ x 5.625 x $10^{-5}$

= 1.7679 x $10^{-4}$

Area of the valve is 0.00018 $m^{2}$ .

From Hooke's law, the force on the safety valve can be determined by;

F = ke

$F_{2}$ = 950 x 0.0085

= 8.075 N

Minimum force, $F_{1}$ , required can be determined by;

$\frac{F_{1} }{A_{1} }$ = $\frac{F_{2} }{A_{2} }$

$\frac{F_{1} }{0.0013}$ = $\frac{8.075}{0.00018}$

$F_{1}$ = $\frac{0.0013 *8.075}{0.00018}$

= 58.32

The minimum force that must be exerted on the piston is 58.32 N.

8 0

3 years ago