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Free_Kalibri [48]
3 years ago
9

If a 600 gram radioactive sample goes through 3 half-lives, how would be left?

Chemistry
1 answer:
olga_2 [115]3 years ago
5 0

Answer:

75 g

Explanation:

1 half life = 600/2 = 300g

2 half life = 300/2 = 150g

3 half life = 150/2 = 75g

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What is the oxidation half-reaction for this unbalanced redox equation? cr2o72– + fe2+ → cr3+ + fe3+ cr3+ → cr2o72– cr2o72– → cr
KatRina [158]

Answer:

6Fe^2+(aq) -------> 6Fe^3+(aq) + 6e

Explanation:

The balanced oxidation half equation is;

6Fe^2+(aq) -------> 6Fe^3+(aq) + 6e

A redox reaction is actually an acronym for oxidation-reducation reaction. Since the both reactions are complementary, there can't be oxidation without reduction and there can't be reduction without oxidation.

The main characteristic of redox reactions is that electrons are transferred in the process. The number of electrons transferred is usually deduced from the balanced reaction equation. For this reaction, the balanced overall reaction equation is;

Cr2O7^2–(aq) + 6Fe^2+(aq) +14H^+(aq)→ 2Cr^3+(aq) + 6Fe^3+ (aq) + 7H2O(l)

It is clear from the equation above that six electrons were transferred. Thus six Fe^2+ ions lost one electron each in the oxidation half equation as shown in the balanced oxidation half equation above.

4 0
3 years ago
The percent yield of a chemical reaction is valuable to many industries. Low percent yields can result in the loss of large amou
aev [14]

Using accurate measurements, using pure chemicals and performing the reaction under the most ideal conditions is important to get a valuable percent yield.

<h3>How we calculate the percent yield?</h3>

Percent yield of any chemical reaction is define as the ratios of the actual yield to the theoretical yield of the product and multiply by the 100.

To get the high percent yield or actual yield of any reaction, we have to perform the reaction under ideal condition because if we not use the standard condition then we get the low rate of reaction. Reactants should be present in the pure form as impurity make unwanted products and reduce the productivity of main product and accurate amount of reactants also important for the spontaneous reaction.

Hence, options (a), (b) & (c) are correct.

To know more about percent yield, visit the below link:

brainly.com/question/8638404

7 0
2 years ago
If I want to accelerate a mass of 3 kg at 5 m/s2 then how much force should I apply?
Stolb23 [73]

<u>Answer:</u> The force that must be applied is 15 N.

<u>Explanation:</u>

Force exerted on the object is defined as the product of mass of the object and the acceleration of the object.

Mathematically,

F=m\times a

where,

F = force exerted = ?

m = mass of the object = 3 kg

a = acceleration of the object = 5m/s^2

Putting values in above equation, we get:

F=3kg\times 5m/s^2=15N

Hence, the force that must be applied is 15 N.

5 0
3 years ago
In which cell structure does MOST of the process of cellular respiration take place?
ahrayia [7]

Mitochondria are rod-shaped organelles are basically considered the power producers of the cell, it converts oxygen and nutrients into adenosine triphosphate or ATP, which is the chemical energy,also known as "currency" of the cell which powers the metabolic actions of the cell. This process is called aerobic respiration and it is the reason animals breathe oxygen. Cellular repiration happens in the mitochodrion. The 3 phases of cellular respiration are Krebs Cycle, Electron Transport and Glycolysis (Fermentation). Glycolysis takes place in the cytoplasm while the Krebs cycle and electron transport take place in the mitochondria.

6 0
3 years ago
Which of the following electron configurations are written incorrectly?
Lynna [10]

Answer:

The electronic configuration that are incorrectly written is 1s²2s³2p⁶, 4s²3d¹⁰4p⁷, 3s¹ and 2s²2p⁴.

Explanation:

The electronic configuration of the elements corresponds to how all the electrons of an element are arranged in energy levels and sub-levels.

There are 7 energy levels —from 1 to 7— whose sublevels are described as s, p, d and f.

All electronic configurations begin with the term "1s" —corresponding to the sublevel s of level 1— so 4s²3d¹⁰4p⁷, 3s¹ and 2s²2p⁴ are incorrectly written. In addition, 4s²3d¹⁰4p⁷ is written incorrectly because is impossible to jump from the sublevel "s" to the sublevel "d" —which is found from level 3 and up— without passing through the sublevel "p".

In the case of 1s²2s³2p⁶, the wrong thing is that the sublevel "s" can only hold two electrons, not three.

The other options are correctly written.

3 0
3 years ago
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