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1 year ago

In 1750, what was the total net rf of non-anthropogenic influences on earth's climate, in w/m2?

1 answer:

3 0

In all of the energy exchanges described, you have seen that the energy gained is balanced by the energy lost. Because there is essentially no annual net gain or loss of energy, Earth’s average temperature remains constant. However, if this fragile balance changes and Earth either gains or loses heat energy, then the global atmospheric temperature would increase or decrease, respectively.

non-anthropogenic particles originating from dust, and anthropogenic particles. The PM of anthropogenic origin is usually contributed by motor vehicle emissions, resuspension of road dust, power generation, industrial.

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A friend asks you how much pressure is in your car tires. You know that the tire manufacturer recommends 30 psi, but it's been a

Bezzdna [24]

Answer:

25 psi

Explanation:

The weight of the car is:

W = mg

W = 1550 kg * 9.8 m/s²

W = 15,190 N

Divided by 4 tires, each tire supports:

F = W/4

F = 15,190 N / 4

F = 3797.5 N

Pressure is force divided by area, so:

P = F / A

P = (3797.5 N) / (0.16 m × 0.14 m)

P ≈ 170,000 Pa

101,325 Pa is the same as 14.7 psi, so:

P ≈ 170,000 Pa × (14.7 psi / 101,325 Pa)

P ≈ 25 psi

8 0

3 years ago

Suppose a net force of 7900 N is applied to slide a 950 kg crate across the floor. Compute the resulting acceleration of the cra

LiRa [457]

Explanation:

F=ma

7900=950a

a=7900/950=8.58m/s^2

4 0

2 years ago

A force of 5N produces an acceleration of 8m/s2 on mass m1, and an acceleration of 24m/s2 on a mass m2. What acceleration would

kotykmax [81]

The acceleration that the same force will provide if both masses are tied together is; 6.0 m/s².

<h3>How to find the Acceleration?</h3>

We are given;

Force; F = 5 N

Acceleration of the first mass, a₁ = 8.0 m/s²

Acceleration of the second mass, a₂ = 24 m/s²

Formula for force is;

F = ma

Let us find both masses; m₁ and m₂.

m₁ = F/a₁

m₂ = F/a₂

Thus;

m₁ = 5/8 kg

m₂ = 5/24 kg

Total mass is; m = m₁ + m₂

m = 5/8 + 5/24

m = 15 + 5/24

m = 20/24 kg

Thus, acceleration if they are both tied together is;

a = F/m

a = 5/(20/24)

a = 6.0 m/s².

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4 0

2 years ago

A vector has a magnitude of 46.0 m and points in a direction 20.0° below the positive x-axis. A second vector, , has a magnitude

irina1246 [14]

Answer with Step-by -step explanation:

We are given that

b. $\mid A\mid=46 m$

$\theta=20^{\circ}$ below the positive x-axis

Therefore, the angle made by vector A in counter clockwise direction when measure from positive x-axis= $x=360-20=340^{\circ}$

x-component of vector A= $A_x=\mid A\mid cosx=46cos 340=46\times 0.94=43.24$

y-Component of vector A= $A_y=\mid A\mid sinx=46sin340=46(-0.34)=-15.64$

Magnitude of vector B=86 m

The vector B makes angle with positive x- axis= $x'=42^{\circ}$

x-component of vector B= $B_x=86cos42=63.64$

y-Component of vector B= $B_y=86sin42=57.62$

Vector A= $A_xi+A_yj=43.24i-15.64j$

Vector B= $B_xi+B_yj=63.64i+57.62j$

Vector C=A+B

Substitute the values

$C=43.24i-15.64j+63.64i+57.62j$

$C=106.88i+41.98j$

c.Direction= $\theta=tan^{-1}(\frac{y}{x})=tan^{-1}(\frac{41.98}{106.88})=21.5^{\circ}$

The direction of the vector C=21.5 degree

6 0

3 years ago

Why does a geostationary satellite must orbit around Earth's equator, rather than in some other orbit (such as around the poles)

LiRa [457]

Answer:

A satellite on non-equatorial orbit would show daily motion even if its period is exactly 1 sidereal day.

Explanation:

5 0

2 years ago