Answer:
Figure-ground organization is a tupe of perceptual grouping that is a vital necessity for recognizing objects trough vision.
Answer:
Motion is a combination of acceleration and velocity(speed). Speed is distance travelled/ time taken. Miles per hour for example. Acceleration is the change in velocity in the time frame of the velocity.
Answer:
The coefficient of kinetic friction between the block and the surface is 0.5
Explanation:
It is given that,
Initial velocity of the block, u = 10 m/s
Time taken by the block to come to rest, t = 2 s
So, final velocity, v = 0
We need to find the coefficient of kinetic friction between the block and the surface. According to second law of motion :
F = ma
And friction force F = -μmg
i.e.
...........(1)
Firstly, we will find the value of a i.e. acceleration
a = -5 m/s²
So, equation (1) becomes :
So, the coefficient of kinetic friction between the block and the surface is 0.5. hence, this is the required solution.
ON EARTH, every kilogram of mass weighs about 2.205 pounds.
So if you know the weight (in pounds), and you know that it was
weighed on Earth, you can simply divide the pounds by 2.205 ,
and you'll get the mass (in kilograms).
I can see that on this science homework, they used 2.2 for the weight
of 1 kilogram expressed in pounds. So just divide the weight by 2.2
to get the mass in kilograms.
(The weight number they gave you is not so random. :-) )
Answer:
a) Andrea's initial momentum, 200 kg m/s
b) Andrea's final momentum, 0
c) Impulse, = - 200 Ns
d) The force that the seat belt exerts on Andrea, - 400 N
Explanation:
Given data,
The initial velocity of the car is, u = 40 m/s
The mass of Andrea, m = 50 kg
The time period of deceleration, a = 0.5 s
The final velocity of the car, v = 0
a) Andrea's initial momentum,
p = mu
= 50 x 40
= 200 kg m/s
b) Andrea's final momentum
P = mv
= 50 x 0
= 0 kg m/s
c) Impulse
I = mv - mu
= 0 - 200
= - 200 Ns
The negative sign indicated that the momentum is decreased.
d) The force that the seat belt exerts on Andrea
F = (mv - mu)t
= (0 - 200) / 0.5
= - 400 Ns
Hence,the force that the seat belt exerts on Andrea is, - 400 N