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Lemur [1.5K]
1 year ago
8

What is the maximum value of the electric field in an electromagnetic wave whose average intensity is 7.35 w/m2 ?

Physics
1 answer:
anastassius [24]1 year ago
7 0

The maximum value of the electric field in an electromagnetic wave is 23.54 V/m.

<h3>What is an electromagnetic wave?</h3>

The oscillations between an electric field and a magnetic field produce waves known as electromagnetic waves, or EM waves. In other words, magnetic and electric fields oscillate to form electromagnetic (EM) waves.

Electromagnetic waves are produced when an electric field and a magnetic field interact. They are referred to as "electromagnetic" waves as a result. An electromagnetic wave's electric field and magnetic field are perpendicular to one another (at right angles). Additionally, they are perpendicular to the EM wave's direction.

In vacuum, EM waves move at a fixed speed of 3.00 x 108 ms-1. Neither the magnetic field nor the electric field can deflect them. However, they might show diffraction or interference. An electromagnetic wave can pass through any medium, including vacuum, solid materials, and air. It can spread or move from one area to another without the use of a medium. On the other hand, mechanical waves (such as sound waves or water waves) require a medium to propagate. Transverse waves include EM waves. The height and distance between the highest and lowest points of two successive waves, respectively, are thus used to measure them.

The highest point of a wave is referred to as the "crest," and the lowest point as the "trough." A variety of frequencies can be created by dividing up electromagnetic waves. The electromagnetic spectrum is what is meant by this. Radio waves, microwaves, infrared waves, X-rays, gamma rays, and other types of waves are EM waves.

To learn more about the, electromagnetic wave visit:

brainly.com/question/12289372

#SPJ4

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Water enters a student's house 10.0 m above the ground through a pipe with a cross section area of 1.00 x 10-4m2 at ground. Insi
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Answer:

(a). V₁ = 10m/s (velocity inside the house), V₂ = 5m/s (velocity at ground level)

(b). P₂ = 236500 Pa

Explanation:

This is quite straight-forward so let us begin by defining the terms given.

Given that;

The cross-section area inside the student's house A₁ = 0.50 0.50 x 10-4m2.

Let us make the velocity of water inside the house be V₁

such that the Volume of water entering the per second is = A₁V₁

Therefore, in 90sec:

45 L =  90 A₁V₁

V₁ = 45 * 10⁻³m³ / 90*0.5*10⁻⁴

V₁ = 10m/s            (velocity of water inside the house)

From the continuity equation we have that;

A₁V₁ = A₂V₂

0.5*10⁻⁴ * 10 = 1*10⁻⁴ V₂

V₂ = 5m/s               (velocity at ground level)

(b). We are told to calculate the water pressure in the pipeline at the ground level.

Using Bernoulli's equation;

P₁ + pgh₁ + 1/2PV₁²  (inside)      =       P₂ + pgh₂ + 1/2PV₂²   (ground level)

1.01*10⁵ + 1000*9.8*10 + 1/2*1000*(10)² = P₂ + 0 + 1/2*1000*(5)²

P₂ (pressure) = 1.01*10⁵Pa

Therefore we have;

101000 + 98000 + 50000 = P₂ + 12500

P₂ = 236500 Pa

cheers I hope this helped !!

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