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kari74 [83]
2 years ago
13

Describe the differences in the tlc of the reaction mixture before heating and after heating and explain the observed change in

rf values.
Chemistry
1 answer:
AVprozaik [17]2 years ago
3 0

Using a thin stationary phase supported by an inert backing, thin layer chromatography (TLC) is a chromatographic technique used to separate the components of a mixture.

It can be carried out on an analytical scale to track the development of a reaction or on a preparative scale to purify minute quantities of a chemical. Because of its simplicity, comparatively low cost, great sensitivity, and rapid separation, TLC is an extensively used analytical method. Similar to all chromatography, TLC works on the premise that a chemical will have varying affinities for the mobile and stationary phases, which will influence how quickly it migrates. TLC aims to produce well-defined, well-separated spots.

Learn more about thin layer chromatography here-

brainly.com/question/10296715

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How much heat in joules is required to heat a 43g sample of aluminum from an initial temperature of 72˚F to a final temperature
Stels [109]
The first step to answering this item is to convert the given temperatures in °F to °C through the equation,

   °C = (°F - 32)(5/9)

initial temperature: 72°F

    °C = (72 - 32)(5/9) = 22.22°C

final temperature: 145°F
   
    °C = (145 - 32)(5/9) = 62.78°C

Substituting to the equation,

    H = mcpdT
    
    H = (43 g)(0.903 J/g°C)(62.78 - 22.22)
   
   H = 1574.82 J

<em>Answer: 1574.82 J</em>
3 0
4 years ago
Identify the reaction type and the products. Al+F2 -&gt;
Lady bird [3.3K]

Answer:

redox and AlF2

Explanation:

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3 years ago
• What policies might people put in place to conserve water levels in lakes and aquifers?
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7 0
4 years ago
Calculate the mass percent composition of sulfur in Al2(SO4)3.
Anastaziya [24]
The molar mass of aluminum sulftae is 342.14 g/mol.

Since the subscript shows that there are 3 sulfurs within the substance, the total mass of sulfur is 96.21g/mol

Now take the mass of the sulfur and divide it by the molar mass of aluminum sulfate, then multiply by 100:
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6 0
3 years ago
Borax (na2b4o7·10h2o; fw = 381.372 g/mol; density = 1.73 g/ml), a primary standard, was used to standardize a solution of hno3.
SashulF [63]
<span>0.06355391 mol The balanced equation for the reaction is Na2B4O7*10H2O + 2 HNO3 = 2 NaNO3 + 4 H3BO3 + 5 H2O So for each mole of Borax to neutralize, it takes 2 moles of HNO3. Calculate number of moles of Borax 0.2619 g / 381.372 g/mol = 0.0006867 mol Moles of HNO3 used = 0.0006867 mol * 2 = 0.0013734 mol Molarity is defined as moles per liter so divide the number of moles used by the volume in liters. So 0.0013734 / 0.02161 = 0.06355391 mol</span>
3 0
4 years ago
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