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kari74 [83]
2 years ago
13

Describe the differences in the tlc of the reaction mixture before heating and after heating and explain the observed change in

rf values.
Chemistry
1 answer:
AVprozaik [17]2 years ago
3 0

Using a thin stationary phase supported by an inert backing, thin layer chromatography (TLC) is a chromatographic technique used to separate the components of a mixture.

It can be carried out on an analytical scale to track the development of a reaction or on a preparative scale to purify minute quantities of a chemical. Because of its simplicity, comparatively low cost, great sensitivity, and rapid separation, TLC is an extensively used analytical method. Similar to all chromatography, TLC works on the premise that a chemical will have varying affinities for the mobile and stationary phases, which will influence how quickly it migrates. TLC aims to produce well-defined, well-separated spots.

Learn more about thin layer chromatography here-

brainly.com/question/10296715

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** ANSWER FAST I WILL MARK YOU BRAINLIEST AND GIVE 20 POINTS * * THIS IS A CHEMISTRY QUESTION SO PLEASE ONLY ANSWER IF YOU ARE G
Anna11 [10]

Answer:

\boxed{\text{ B. Increase the temperature and decrease the pressure.}}

Explanation:

Let's say the reaction is

R ⇌ 2P; endothermic

I like to consider heat as if it were a reactant or a product in a chemical equilibrium.

Another way to write the equilibrium would be

heat + R ⇌ 2P

According to Le Châtelier's Principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

Let's consider each of the stresses in turn.

(i) Changing the temperature

If you want to increase the amount of product, you increase the temperature. The system will try to get rid of the added heat by shifting to the right, thus forming more product.

(ii) Changing the pressure

If R and P are liquids or solids or in aqueous solution, changing the pressure will have no effect. Something must be in the gas phase for a change in pressure to affect the position of equilibrium.

If P is a gas, the equilibrium is

heat + R ⇌ 2P(g)

Then, decreasing the pressure will produce more P. If you reduce the pressure, the system will respond by shifting to the right (the side with more gas molecules) to produce more P and bring the pressure back up

5 0
3 years ago
Is the equation for reaction 1 balanced? Explain your reasoning. If the reaction is not balanced, then state how you would balan
sveticcg [70]

Answer:

Reaction is already balanced

Explanation:

The equation in reaction 1 is given as;

CH3COOH + NaHCO3 --> CO2 + H2O +  Na+   +  CH3COO-

The reaction is already balanced. This is because the umber of atoms of elements in the reactant is equal to that of the products

Carbon

Reactant = 2 + 1 = 3

Product = 2 + 2 = 3

Hydrogen

Reactant = 3 + 1 + 1 = 5

Product = 2 + 3 = 5

Oxygen

Reactant = 2 + 3 = 5

Product = 2 +1 + 2 = 5

Sodium

Reactant = 1

Product = 1

3 0
3 years ago
A _____ is a new substance formed in a chemical reaction.
Lorico [155]
B. product
Think about it like this: a company produces products, not coefficients.
5 0
3 years ago
The melting point of H₂O(s) is 0 °C. Would you expect the melting point of H₂S(s) to be 85 °C, 0 °C or -85 °C.? Justify your cho
dimulka [17.4K]

Answer:

-85 °C

Explanation:

O and S are in the same group( Group 16). Since S is below O it's atomic mass is higher than O. So molar mass of H2S is higher than H2O. The strength of Vanderwaal Interactions ( London dispersion forces) increases when the molar mass increases. However, only H2O can form H bonds with each other. This is because electronegativity of O is higher than S and therefore H in H2O has a higher partial positive charge than H of H2S.

H bond dominate among these 2 types of forces so the strength of attractions between molecules is higher in H2O than H2S. Therefore more energy should be supplied for H2O to break inter

molecular forces and convert from solid to liquid state than H2S. So mpt of H2O must be higher than that of H2S.

5 0
3 years ago
What is the name of this alkane?
Otrada [13]
It's a cyclohexane ring with an ethyl group at 1 and a methyl group at 3. The Ethyl group is bigger and more important group get's the first position.

1-ethyl-3-methylcyclohexane
3 0
4 years ago
Read 2 more answers
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