Answer:
Answer is explained in the explanation section below.
Explanation:
Solution:
Note: This question is incomplete and lacks very important data to solve this question. But I have found the similar question which shows the profiles about which question discusses. Using the data from that question, I have solved the question.
a) We need to find the major species from A to F.
Major Species at A:
1. 
Major Species at B:
1.
2. 
Major Species at C:
1.
Major Species at D:
1.
2. 
Major Species at E:
1.
Major Species at F:
1.
b) pH calculation:
At Halfway point B:
pH = pK
+ log[
]/[H
]
pH = pK = 6.35
Similarly, at halfway point D.
At point D,
pH = pK
+ log [H]/[H2]
pH = pK = 10.33
Volume of osmium = 1.01(0.223)(0.648) = 0.14595 cm3
Density = mass / volume
So density x volume = mass of osmium
22.6 x 0.14595 = 3.29845 g
<u>Answer:</u> The equilibrium constant for the given equation is 0.0315
<u>Explanation:</u>
We are given:
Total pressure in the container = 0.596 atm
The given chemical equation follows:
<u>Initial:</u> -
<u>At eqllm:</u> - 2x x
Evaluating the value of 'x'
The expression of 
for above equation follows:
The partial pressure of pure solids and pure liquids are taken as 1 in the equilibrium constant expression.
Putting values in above expression, we get:
Hence, the equilibrium constant for the given equation is 0.0315
Answer:
The structure is shown in the diagram.
Explanation:
Lewis structure : In order to draw Lewis structure we will calculate the total number of valence electrons in the molecule.
The valence electrons from Cl : 7
The valence electrons from O = 3 X 6 = 18
Charge negative so more electrons = 2
total electrons = 7 + 18 +2 = 27
Now we will distribute the electrons on each atom and in between atoms as shown in the diagram.
Answer:
To calculate the volume we must first find the number of moles
Number of moles (n ) = mass / Molar mass (M)
Since oxygen is diatomic
M of oxygen = 16 × 2 = 32g/mol
n = 16 / 32 = 0.5mol
Next we use the formula
V = n × V(dm³)
where V is the volume
V(dm³) is the volume of 1 mole of a substance at s.t.p which is
22.4dm³
Volume of oxygen gas at s.t.p is
0.5 × 22.4dm³
= 11.20dm³
Hope this helps you
