Answer:
![d=0.165m](https://tex.z-dn.net/?f=d%3D0.165m)
Explanation:
Given
,
,
,![v=2\frac{rev}{s}](https://tex.z-dn.net/?f=v%3D2%5Cfrac%7Brev%7D%7Bs%7D)
The tension of the spring is
![F_{k}=K*x_{1}=m*g](https://tex.z-dn.net/?f=F_%7Bk%7D%3DK%2Ax_%7B1%7D%3Dm%2Ag)
![K=\frac{m*g}{x_{1}}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7Bm%2Ag%7D%7Bx_%7B1%7D%7D)
![K=\frac{0.25kg*9.8m/s^2}{0.05m}=49N/m](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B0.25kg%2A9.8m%2Fs%5E2%7D%7B0.05m%7D%3D49N%2Fm)
The force in the spring is equal to centripetal force so
![F_{c}=\frac{m*v^2}{r}](https://tex.z-dn.net/?f=F_%7Bc%7D%3D%5Cfrac%7Bm%2Av%5E2%7D%7Br%7D)
![v=w*r=2\pi*r](https://tex.z-dn.net/?f=v%3Dw%2Ar%3D2%5Cpi%2Ar)
But Fc is also
Fc=KxΔr
![F_{c}=K*(r-x_{2})](https://tex.z-dn.net/?f=F_%7Bc%7D%3DK%2A%28r-x_%7B2%7D%29)
Replacing
![m*4\pi^2*r=K*(r-x_{2})](https://tex.z-dn.net/?f=m%2A4%5Cpi%5E2%2Ar%3DK%2A%28r-x_%7B2%7D%29)
![0.25kg*4\pi^2*r=49*(r-0.04m)](https://tex.z-dn.net/?f=0.25kg%2A4%5Cpi%5E2%2Ar%3D49%2A%28r-0.04m%29)
![r=0.205m](https://tex.z-dn.net/?f=r%3D0.205m)
total distance is
![d=0.205-0.04=0.165m](https://tex.z-dn.net/?f=d%3D0.205-0.04%3D0.165m)
Answer:
a = -5.10 m/s^2
her acceleration on the rough ice is -5.10 m/s^2
Explanation:
The distance travelled on the rough ice is equal to the width of the rough ice.
distance d = 5.0 m
Initial speed u = 9.2 m/s
Final speed v = 5.8 m/s
The time taken to move through the rough ice can be calculated using the equation of motion;
d = 0.5(u+v)t
time t = 2d/(u+v)
Substituting the given values;
t = 2(5)/(9.2+5.8)
t = 2/3 = 0.66667 second
The acceleration is the change in velocity per unit time;
acceleration a = ∆v/t
a = (v-u)/t
Substituting the values;
a = (5.8-9.2)/0.66667
a = -5.099974500127
a = -5.10 m/s^2
her acceleration on the rough ice is -5.10 m/s^2
KE = 1/2 mv^2 is the relationship betwee mass and kinetic energy
Answer:
send the wagon down a higher hill
Answer:
A- Astronomical body
C- Galaxy
D- Comet
B- Moon
Hope this helps you! Have a great day!