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1 year ago

A train accelerates steadily from 4.m.s.-1 to 20.m.s.-1 in 100 seconds

Physics

1 answer:

kozerog [31]1 year ago

6 0

Answering question assuming that we need to calculate how far it will travel in a given time.

A train accelerates steadily from 4 m/s to 20 m/s in 100 seconds then it will travel 1200 m in a given time.

Given:

Initial velocity u = 4m/s

Final velocity v = 20m/s

Time t = 100s

We need to find out the distance covered in given time.

Distance =?

For finding distance, we need to find acceleration first.

Here we can apply kinematic equations as acceleration is steady as given in question.

So applying the first kinematic equation to find acceleration first.

a = v-u/t

a = 20-4/100

a = 16/100

a = 0.16m/s²

Now applying second kinematic equation

S=ut+ 1/2at²

s = 4 x 100+ 1/2 x 0.16 x 100 x 100

s = 400 + 800 = 1200 m

Thus a train accelerates steadily from 4 m/s to 20 m/s in 100 seconds then it will travel 1200 m in a given time.

To learn more about the Kinematic equation application please click on the link brainly.com/question/26469691

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1 year ago

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3 years ago

A train accelerates steadily from 4.m.s.-1 to 20.m.s.-1 in 100 seconds​

A train accelerates steadily from 4.m.s.-1 to 20.m.s.-1 in 100 seconds