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ipn [44]
2 years ago
6

A rock is dropped from a 134-m-high cliff. how long does it take to fall (a) the first 67.0 m and (b) the second 67.0 m?

Physics
1 answer:
____ [38]2 years ago
4 0

A rock is dropped from a 100-m-high cliff. How long do the first 50 meters and the second 50 meters take to fall?

(a) The first 50 meters:

h1 = 0.5 x a x t12

50 m = 0.5% x 9.8% x t12

t1 = 3.19 s

50 meter fall time equals 3.19 seconds.

(a) Counting all 100 meters:

h2 = 0.5 x a x t22

100 m = 0.5% x 9.8% x t22

t2 = 4.52 s

Time to fall 50 meters is equal to t2 - t1 = 1.33 s.

<h3>What is meter?</h3>

The Earth's circumference is around 40000 km, according to the original definition of the metre in 1793, which was one ten-millionth of the distance between the equator and the North Pole on a great circle. The metre was redefined in 1799 using a model metre bar (the actual bar used was changed in 1889). The definition of the metre in terms of a certain number of wavelengths of a specific krypton-86 emission line was made in 1960.

To know more about meter, visit;

brainly.com/question/14475998

#SPJ4

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'D' trailed off in the middle, and we don't know WHAT it was talking about.

'B' is the only correct statement.


6 0
3 years ago
How many minutes does light need to travel from the sun to Jupiter?
nydimaria [60]

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3 0
3 years ago
Compare and contrast chemical reactions and nuclear reactions in terms of particles involved . Select all the statements that ap
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5 0
3 years ago
A 0.8 g object is placed in a 534 N/C uniform electric field. Upon being released from rest, it moves 12 m in 1.2 s. Determine t
Mice21 [21]

Explanation:

It is given that,

Mass of the object, m = 0.8 g = 0.0008 kg

Electric field, E = 534 N/C

Distance, s = 12 m

Time, t = 1.2 s

We need to find the acceleration of the object. It can be solved as :

m a = q E.......(1)

m = mass of electron

a = acceleration

q = charge on electron

"a" can be calculated using second equation of motion as :

s=ut+\dfrac{1}{2}at^2

s=0+\dfrac{1}{2}at^2

a=\dfrac{2s}{t^2}

a=\dfrac{2\times 12\ m}{(1.2\ s)^2}

a = 16.67 m/s²

Now put the value of a in equation (1) as :

q=\dfrac{ma}{E}

q=\dfrac{0.0008\ kg\times 16.67\ m/s^2}{534\ N/C}

q = 0.0000249 C

or

q=2.49\times 10^{-5}\ C

Hence, this is the required solution.

5 0
3 years ago
Q7, how the ans is 4.9 not 19.6?
taurus [48]

the answer is c in question 7

5 0
1 year ago
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