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Yakvenalex [24]
3 years ago
8

NEED ANSWERED ASAP!! will give brainliest!

Physics
1 answer:
kotegsom [21]3 years ago
8 0
The kinetic energy of any moving object is

            K.E.  =  (1/2) (mass) (speed)² .
 
To use this simple formula, the 'mass' has to be in kilograms,
and the 'speed' has to be in meters-per-second. 

You can see that we have a slight problem that has to be cleaned up:
The speed in the question is given in "kilometers per hour", but we'll
need it in "meters per second".  So let's convert that right now: 

       (600 km/hour) x (1 hour / 3600 seconds) x (1000 meters / km)

    =    (600 x 1 x 1000 / 3600)    (km-hour-meters / hour-second-km)

    =              166.67  meters/second .

Now we're ready to plug numbers into the formula for K.E.

                  (1/2) (mass) (speed)²

            =    (1/2) (80,000 kg) (166.67 m/s)²

            =           (40,000 kg) (27,777.8 m²/s²)

            =                1,111,111,111  kg-m²/s²

            =                 1.1... x 10⁹  Joules   (choice D) 

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Quick Physics Question
sveticcg [70]
It is Real,Virtual,The Same Size, Inverted
8 0
3 years ago
town q and town p were 119 km apart. van drove from town q to town p at an average speed of 70 km/h. how much sooner would be ha
Vilka [71]

Answer:

0.3 hours sooner than the normal time of arrival

Explanation:

Finding the difference in time of arrival of both speed will help know how much sooner.

Given:

Distance = 119 km

Speed 1 = 70 km/h

Speed 2 = 85 km/h

Time = Distance / Speed

For the time taken at the first speed

Time = 119/70

         = 1.7 hours

For the time taken at the second speed

Time = 119/85

        = 1.4 hours

∴ 1.7 hours - 1.4 hours

= 0.3 hours sooner

3 0
3 years ago
Which of the following is a class of wave in physics
schepotkina [342]

Answer:

sorry cant find the answer but i hope you got it right and if you didnt youll still do great

Explanation:

8 0
3 years ago
Read 2 more answers
A 0.22 kg mass at the end of a spring oscillates 2.9 times per second with an amplitude of 0.13 m .
andre [41]

Answer:

2.3687599 m/s

0.91106 m/s

0.617213012 J

Explanation:

f = Frequency = 2.9\ Hz

A = Amplitude = 0.13 m

k = Spring constant

m = Mass of object = 0.22 kg

Angular velocity is given by

\omega=2\pi f\\\Rightarrow \omega=2\pi 2.9\\\Rightarrow \omega=18.22123\ rad/s

Velocity is given by

V=A\omega\\\Rightarrow V=0.13\times 18.22123\\\Rightarrow V=2.3687599\ m/s

Speed when it passes the equilibrium point is 2.3687599 m/s

Frequency is given by

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}\\\Rightarrow k=m4\pi^2f^2 \\\Rightarrow k=0.22\times 4\pi^2\times 2.9^2\\\Rightarrow k=73.04296\ N/m

x = Displacement = 0.12 m

In this system the energies are conserved

\dfrac{1}{2}kA^2=\dfrac{1}{2}mv^2+\dfrac{1}{2}kx^2\\\Rightarrow v=\sqrt{\dfrac{k(A^2-x^2)}{m}}\\\Rightarrow v=\sqrt{\dfrac{73.04296(0.13^2-0.12^2)}{0.22}}\\\Rightarrow v=0.91106\ m/s

The speed when it is 0.12 m from equilibrium is 0.91106 m/s

The energy in the system is given by

E=\dfrac{1}{2}kA^2\\\Rightarrow E=\dfrac{1}{2}\times 73.04296\times 0.13^2\\\Rightarrow E=0.617213012\ J

The total energy of the system is 0.617213012 J

4 0
4 years ago
4. Compare reflecting telescopes and refracting<br> telescopes.
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A reflecting will have a mirror on the bottom where the light will bounce off a retracting uses lenses that focus the light
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4 years ago
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