It is Real,Virtual,The Same Size, Inverted
Answer:
0.3 hours sooner than the normal time of arrival
Explanation:
Finding the difference in time of arrival of both speed will help know how much sooner.
Given:
Distance = 119 km
Speed 1 = 70 km/h
Speed 2 = 85 km/h
Time = Distance / Speed
For the time taken at the first speed
Time = 119/70
= 1.7 hours
For the time taken at the second speed
Time = 119/85
= 1.4 hours
∴ 1.7 hours - 1.4 hours
= 0.3 hours sooner
Answer:
sorry cant find the answer but i hope you got it right and if you didnt youll still do great
Explanation:
Answer:
2.3687599 m/s
0.91106 m/s
0.617213012 J
Explanation:
f = Frequency = 
A = Amplitude = 0.13 m
k = Spring constant
m = Mass of object = 0.22 kg
Angular velocity is given by

Velocity is given by

Speed when it passes the equilibrium point is 2.3687599 m/s
Frequency is given by

x = Displacement = 0.12 m
In this system the energies are conserved

The speed when it is 0.12 m from equilibrium is 0.91106 m/s
The energy in the system is given by

The total energy of the system is 0.617213012 J
A reflecting will have a mirror on the bottom where the light will bounce off a retracting uses lenses that focus the light