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siniylev [52]
2 years ago
15

A schematic can tell an electrician that the switches are normally

Physics
1 answer:
In-s [12.5K]2 years ago
5 0

The correct answer is Option B) Open.

A schematic can tell an electrician that the switches are normally open

until the sensor senses smoke.

<h3>What is a schematic diagram?</h3>

A simple, understandable graphical representation of a plan or model is called a schematic diagram. Simple lines and symbols are used in schematics to convey details like what, how, and where. A schematic diagram's primary role is to highlight circuit components and the relationships between them. Schematics are a very useful tool for troubleshooting since they show which parts are connected in series or parallel and how.

An example of an electrical switch is one that is normally open. A typically open switch remains "off" when it is not compressed. The inside electrical connections are to blame for this. In a typically open switch, the contacts are open when the switch is off. This indicates that the switch is "off" because the electrical connection is damaged.

To know more about schematic diagram, visit:

brainly.com/question/14323677

#SPJ4

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A nearsighted person wants to see an apple that is 7 meters away but can only clearly see objects that are at most 62 cm away fr
natulia [17]

Answer:

The power of the corrective lenses is 3.162 D.

Explanation:

Given that,

Object distance = 70 cm

Image distance = 62 cm

Distance between eyes and glasses = 2.5 cm

Eyeglasses made of diverging corrective lenses can help her to see the apple clearly

So now ,

Object distance from glass =70-2.5 = 67.5 cm

Image distance from glass = 62-2.5 = 59.5 cm

We need to calculate the focal length

Using formula for focal length

\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}

\dfrac{1}{f}=-\dfrac{1}{59.5}-\dfrac{1}{67.5}

\dfrac{1}{f}=-\dfrac{508}{16065}\ cm

We need to calculate the power of lens

Using formula of power

P=\dfrac{100}{f}

P=-\dfrac{508}{16065}\times100

P=-3.162 \ D

Negative sign shows the lens is diverging.

Hence, The power of the corrective lenses is 3.162 D.

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I believe the answer is D. <span>The hypothesis is revised and another experiment is conducted.</span>
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