0.1875 mol of Na2CO3 needed to react with the 750 mL of 0.250 M H2SO4.
The given reaction between Na2CO3 and H2SO4 are already balanced.
Na2CO3 + H2SO4 → Na2SO4 + CO2.H2O
First, let us determine the number of moles of H2SO4.
Molarity (mol/L) = number of moles of H2SO4 / volume of H2SO4
0.250 M = number of moles of H2SO4 / [(750 mL)(1 L/1000 mL)]
number of moles of H2SO4 = 0.1875 mol
Then, let us determine the number of moles of Na2CO3 that would react with 0.1875 mol H2SO4.
number of moles of Na2CO3 = moles of H2SO4 * stoichiometric ratio
number of moles of Na2CO3 = 0.1875 mol H2SO4 * (1 mol Na2CO3/ mol H2SO4)
number of moles of Na2CO3 = 0.1875 mol Na2CO3
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