Partial would be the answer your looking for
Based on octet rule, elements would fill up their
outermost shell with 8 electrons to be stable. In this case, Carbon has 4
valence on its outer shell, Hydrogen has only 1 valence, while Bromine has 7. Therefore
the total valence electrons are:
total valence = 4*4 + 1*6 + 7*2 = 16 + 6 + 14
<span>total valence = 36</span>
Compounds have the lowest percentage of gold content by weight is <u>Aui3</u>
M(Au) =197g/mol
M(O) =16g/mol
M(H)=1g/mol
M(Cl)=35g/mol
M(I)=53 g/mol
1) M=214g/mol =197+1+16
197/214= 0.921
2) M=248g/mol =
197/248=0.794
3) M=302g/mol =
197/302=0.652
4) M=356g/mol =
197/356=0.5533
<u>Explanation:</u>
Iodine is the heaviest out of I, Cl and OH. The items on your list hold less and less gold by mass as you go down. The gold dissolution percentage in a hypochlorite-iodide mix-up is completely conditioned upon the solution pH. So the iodine has the lowest gold content percentage.