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zhuklara [117]
3 years ago
6

The specific heat capacity of liquid water is 4.18 J/g oC. Calculate the quantity of energy required to heat 1.50 g of water fro

m 26.5oC to 83.7oC. (Ignore significant figures for this problem.)
Chemistry
1 answer:
natima [27]3 years ago
5 0

Answer: The quantity of heat required is 358.644 J.

Explanation:

Given: Specific heat capacity = 4.18 J/g^{o}C

Mass = 1.50 g

T_{1} = 26.5^{o}C

T_{2} = 83.7^{o}C

Formula used to calculate heat energy is as follows.

q = m \times C \times (T_{2} - T_{1})

where,

q = heat energy

m = mass

C = specific heat capacity

T_{1} = initial temperature

T_{2} = final temperature

Substitute the values into above formula as follows.

q = m \times C \times (T_{2} - T_{1})\\= 1.50 \times 4.18 J/g^{o}C \times (83.7 - 26.5)^{o}C\\= 358.644 J

Thus, we can conclude that quantity of heat required is 358.644 J.

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Answer:

250000 μL

Explanation:

If         1 L = 1000 mL

Then  X L = 250 mL

X = (1 × 250) / 1000 = 0.25 L

Now we can calculate the number of microliters (μL) in 0.25 L:

if        1 μL = 10⁻⁶ L

then   X μL = 0.25 L

X = (1 × 0.25) / 10⁻⁶  =250000 μL

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3 years ago
For motion maps that illustrate accelerated motion what does a new level indicate
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What is the wavelength, in nm, of the light photon emitted by a hydrogen atom when an electron goes from n
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Hence, the wavelength of the photon associated is 1282 nm.

Explanation:

8 0
3 years ago
Predict the sign of the entropy change,Delta S, for each of the following reactions:The signs are either going to be pos or nega
algol [13]

Answer: a) Pb^{2+}(aq)+2Cl^-(aq)\rightarrow PbCl_2(s):  negative

b)  CaCO_3(s)\rightarrow CaO(s)+CO_2(g) : positive

c) 2NH_3(g)\rightarrow N_2(g)+3H_2(g): positive.

d) P_4(g)+5O_2(g)\rightarrow P_4O_{10}(s) : negative

e) C_4H_8(g)+6O_2(g)\rightarrow 4CO_2(g)+4H_2O(g):  positive.

f) I_2(s)\rightarrow I_2(g) : positive.

Explanation:

Entropy is the measure of randomness or disorder of a system. If a system moves from  an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.

\Delta S is positive when randomness increases and \Delta S is negative when randomness decreases.

a) Pb^{2+}(aq)+2Cl^-(aq)\rightarrow PbCl_2(s)

As ions are moving to solid form , randomness decreases and thus sign of \Delta S is negative.

b) CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

As solid is changing to gas, randomness increases and thus sign of \Delta S is positive.

c) 2NH_3(g)\rightarrow N_2(g)+3H_2(g)

As 2 moles of reactants are converted to 4 moles of products , randomness increases and thus sign of \Delta S is positive.

d) P_4(g)+5O_2(g)\rightarrow P_4O_{10}(s)

As gas is changing to solid, randomness decreases and thus sign of \Delta S is negative.

e) C_4H_8(g)+6O_2(g)\rightarrow 4CO_2(g)+4H_2O(g)

As 7 moles of reactants are converted to 8 moles of products , randomness increases and thus sign of \Delta S is positive.

f) I_2(s)\rightarrow I_2(g)

As solid is changing to gas, randomness increases and thus sign of \Delta S is positive.

6 0
3 years ago
I need help pleasee
Readme [11.4K]

Answer:

Explanation:

6. Where on the graph does adding heat energy NOT raise the temperature?

What is the heat energy DOING if it's not raising the temperature?  :its being compressed I believe its vaporizing

7. What is temperature A called?  Freezing

8. What is temperature B called? Vaporizing

4 0
3 years ago
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