Answer:
Wmoon = 131 [N]
Explanation:
We know that the weight of a body is equal to the product of mass by gravitational acceleration.
Since we are told that the gravitational acceleration of the moon is equal to one-sixth of the acceleration of Earth's gravitation. Then we must multiply the value of Earth's gravitation by one-sixth.
![w_{moon}=\frac{1}{6} *m*g\\w_{moon}=\frac{1}{6} *80*9.81\\w_{moon}=130.8 [N] = 131 [N]](https://tex.z-dn.net/?f=w_%7Bmoon%7D%3D%5Cfrac%7B1%7D%7B6%7D%20%2Am%2Ag%5C%5Cw_%7Bmoon%7D%3D%5Cfrac%7B1%7D%7B6%7D%20%2A80%2A9.81%5C%5Cw_%7Bmoon%7D%3D130.8%20%5BN%5D%20%3D%20131%20%5BN%5D)
Complete question:
A uniform electric field is created by two parallel plates separated by a
distance of 0.04 m. What is the magnitude of the electric field established
between the plates if the potential of the first plate is +40V and the second
one is -40V?
Answer:
The magnitude of the electric field established between the plates is 2,000 V/m
Explanation:
Given;
distance between two parallel plates, d = 0.04 m
potential between first and second plate, = +40V and -40V respectively
The magnitude of the electric field established between the plates is calculated as;
E = ΔV / d
where;
ΔV is change in potential between two parallel plates;
d is the distance between the plates
ΔV = V₁ -V₂
ΔV = 40 - (-40)
ΔV = 40 + 40
ΔV = 80 V
E = ΔV / d
E = 80 / 0.04
E = 2,000 V/m
Therefore, the magnitude of the electric field established between the plates is 2,000 V/m
Answer:
well its simple the worker wouldn't actually be working
Answer:
Velocity of airplane is 500 km/h
Velocity of wind is 40 km/h
Explanation:
= Velocity of airplane in still air
= Velocity of wind
Time taken by plane to travel 1150 km against the wind is 2.5 hours
Time taken by plane to travel 450 km against the wind is 50 minutes = 50/60 hours
Subtracting the two equations we get
Applying the value of velocity of wind to the first equation
∴ Velocity of airplane in still air is 500 km/h and Velocity of wind is 40 km/h
