Answer:
7.888m
Explanation:
Given:
frequency 'f'= 90Hz
velocity of the sound 'v' = 340 m /sec
The wavelength of the wave is given by,
λ= v/f => 340/90
λ= 3.777m
The destructive interference condition is givn by
Δd= λ
where, m=0,1,2,3,..
m=0, for minimum destructive interference
Δd= x 3.777
Δd=1.888
Therefore, the required distance is
=
+ Δd => 6 + 1.888
= 7.888m
Thus, So the speaker should be placed at 7.888 m
Answer:
The distance from the central bright spot are and
.
Explanation:
Given that,
Wavelength = 490 nm
Distance y= 15 mm
Length L=1.6 m
New wavelength = 670
We need to calculate the distance from the central bright spot
Using formula of distance
Put the value into the formula
We need to calculate the distance from the central bright spot for new wavelength
Using formula of distance
Put the value into the formula
Hence, The distance from the central bright spot are and
.