A kangaroo can jump over an object 2.40 m high. calculate how long in seconds it is in the air. (3 sig figs
1 answer:
A kangaroo will stay 0.699s in the air when he jumps.
<h3>What motion does the projectile make?</h3>A projectile is an object that is launched vertically into the air and moves while being pulled by gravity. A projectile is an object that is launched into the air horizontally and moves regardless of gravity.
<h3>How do you determine the rate of descent?</h3>G = -9.81 m/s2 is the acceleration of gravity close to the earth. Simply multiply the acceleration of gravity by the period since the object was released to determine the object's speed (or velocity). In other words, velocity is equal to -9.81 m/s2 * time, or V = gt.
<h3>According to the given information:</h3>From the conversion of energy =
t = √(2h/g)
= √((2 x 2.40) / 9.8)
=0.699 s
A kangaroo will stay 0.699s in the air when he jumps.
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Answer:
<h2>10 m/s²</h2>Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
m is the mass
f is the force
From the question we have
We have the final answer as
<h3>10 m/s²</h3>Hope this helps you
Answer:
-4.0 N
Explanation:
Since the force of friction is the only force acting on the box, according to Newton's second law its magnitude must be equal to the product between mass (m) and acceleration (a):
(1)
We can find the mass of the box from its weight: in fact, since the weight is W = 50.0 N, its mass will be
And we can fidn the acceleration by using the formula:
where
v = 0 is the final velocity
u = 1.75 m/s is the initial velocity
t = 2.25 s is the time the box needs to stop
Substituting, we find
(the acceleration is negative since it is opposite to the motion, so it is a deceleration)
Therefore, substituting into eq.(1) we find the force of friction:
Where the negative sign means the direction of the force is opposite to the motion of the box.