Question

One wire in a high-voltage transmission line carries 1000 A starting at 700kV for a distance of 100 mi. If the resistance in the wire is 0.500 ω/mi , what is the power loss due to the resistance of the wire?

Answer 1

The electrical power loss is 50 megawatts.

What is the power loss due to the resistance of the wire?

The electrical power loss, P due to the resistance of the wire is calculated as follows:

• Power = I²R

Given the following data:

Current = 1000A

Voltage = 700 KV

Resistance per length = 0.5 Ω/mi

Length of wire = 100 miles

Resistance, R = 0.5 Ω/mi x 100 mi

R = 50Ω

Therefore;

P = (1000 A)² x 50 Ω

P = 50,000,000 W

P = 50 megawatts

In conclusion, the electrical power loss is obtained from the current and the resistance.

Learn more about power loss at: brainly.com/question/13080026

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