Answer:
The ball will fly tangential to the original circle
Explanation:
The image here is missing, however we can still answer to the question.
In fact, the circular motion of the ball when it is tied to the rope is a combination of two separate effects:
1- The centripetal force, in the form of the tension in the rop, that pulls the ball at any time towards the centre of the circular path
2- The inertia of the ball, which tends to continue its motion in a straight direction, tangential to the circle and perpendicular to the direction of the centripetal force
When child let the string go, there is no more tension in the string acting on the ball, and therefore, there is no longer a centripetal force.
As a result, number 1) disappears, and therefore there is only the inertia of the ball that will determine its motion: and therefore, the ball will continue its motion straight in a direction tangential to the original circle.
Answer:
Molar concentration of S₂ is 1.77×10⁻⁶M
Explanation:
For the reaction:
2H₂S(g) ⇄ 2H₂(g) + S₂(g)
The equilibirum constant, K, is defined as:
<em>(1)</em>
Concentrations in equilibirum are:
[H₂S] : 0,163/0.500L - X
[H₂] : 0,0500/0.500L + X
[S₂] : X
Replacing the concentrations and the equilibrium value in (1):
![K = \frac{[X][0.1+X]^2}{[0326-X]^2}](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B%5BX%5D%5B0.1%2BX%5D%5E2%7D%7B%5B0326-X%5D%5E2%7D)
1.67x10⁻⁷ = X (X² + 0.2X + 0.01) / (X² -0.652X + 0.106)
1.67x10⁻⁷X² - 1.09x10⁻⁷X + 1.77x10⁻⁸ = X³ + 0.2X² + 0.01X
0 = X³ + 0.2X² + 0.01X - 1.77x10⁻⁸
Solving for X:
X = 1.77×10⁻⁶
As [S₂] = X, <em>molar concentration of S₂ is 1.77×10⁻⁶M</em>
I hope it helps!
Answer: the empirical formula is C3H4O3
Explanation:Please see attachment for explanation
E = mc2
Born on March 14, 1879, Albert Einstein is best known for developing the theory of relativity and the mass-energy equivalence formula E = mc2, often dubbed as 'the world's most famous equation'.