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Mrrafil [7]
3 years ago
7

Need helppp number 5

Physics
2 answers:
horsena [70]3 years ago
5 0

Answer:

1768 meters

Explanation:

Distance = speed x time.

(340 m/s) x (5.2 s) = 1768 m

artcher [175]3 years ago
4 0
I think the answer is 1768
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A car travels 40km/hr for 2 hours and 55km/hr for 2 hours how far has the car traveled what’s its average velocity?
vfiekz [6]

Answer;

Average speed  = 47.5 km/hr

Explanation and solution;

Average Speed = Total distance /Total time

Total distance;

-In the first two hours travelling at 40km/hr, total distance traveled is 80km.

(40 × 2) = 80 km

-In next two hours distance covered is 110 km. (55 ×2)

Total distance = 110 + 80 = 190 km

Total time = 2 + 2 = 4 hours

Average Speed = Total distance /Total time

                          = 190/4

                         = 47.5 km/hr

7 0
3 years ago
A simple pendulum takes 128s to complete 40 oscillations what is the time period of the pendulum
Serhud [2]

Explanation:

Parameters

Number of oscillation = 40 oscillations

Time of oscillation = 128s

Formular

Period (T) = <u>No of oscillation</u>

Time taken

T = <u>128</u>

40

T=3.2s

3 0
3 years ago
The students in a class had the following scores on a test:
Brilliant_brown [7]
C. 76 I just did the question earlier
6 0
3 years ago
Read 2 more answers
On an icy winter day, the coefficient of friction between the tires of a car and a roadway is reduced to 1/4 its value on a dry
Naddik [55]

Answer:

50%

Explanation:

For the particular case we assume that the centripetal force is equal to the frictional force. Starting from this, we realize that while the car takes a curve, which allows it to not leave the track, it is the friction force that adheres it to the floor, in this way,

F_c = F_f

The values of these equations are given by,

F_c = \frac{mv^2}{R}

F_f = \mu N = \mu mg

Equating the terms

\frac{mv^2}{R} = \mu mg

v = \sqrt{\mu Rg}

Both gravity and radius are values that during the trajectory with constants, so

v \approx \sqrt{\mu}

The difference comes in winter and dry, so,

\mu_{dry} = \mu

as in winter it is a quarter, you have to,

\mu_{winter} = \frac{1}{4} \mu_{dry} = \frac{1}{4} \mu

Performing the proportion we have to

\frac{\mu_{winter}}{\mu_{dry}} = \frac{\sqrt{\mu/4}}{\mu}

\frac{\mu_winter}{\mu_{dry}} = \frac{1}{2} = 0.5

We can conclude that the new value for this speed is 50% of its value on a dry day.

7 0
3 years ago
A 4kg block slides freely across a rough surface such that the block slows down with an acceleration of −1.25 m/s2 . What is the
Sophie [7]

Answer:

The coefficient of kinetic friction between the block and the surface is 0.127.

Explanation:

Given that,

The mass of a block, m = 4 kg

The acceleration of the block, a = -1.25 m/s²

We need to find the coefficient of kinetic friction between the block and the surface. The force of friction is given by :

F=\mu mg\\\\ma=\mu mg\\\\\mu=\dfrac{a}{g}\\\\\mu=\dfrac{1.25}{9.8}\\\\\mu=0.127

So, the coefficient of kinetic friction between the block and the surface is 0.127.

6 0
3 years ago
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