help show if a straight "trend line" represents the experimental data
Answer: potential to kinetic and then potential energies
Explanation:
Answer: 6 and 8 would be side lengths because if it has a scale factor of 2 then you multiply the ones on the chart.
Explanation:Go find one
Answer:
the selected configuration is PARALLEL
Explanation:
There are two ways to connect electrical circuits.
In series in this type of circuit the equipment is connected to the same line, in this case the current of the circuit circulates through all the inputs is the same, but the voltage in each one is a part of the total voltage, this circuit has the problem that if an appliance is disconnected or damages the power and the entire circuit is interrupted
V_total = ∑ V_i
In a parallel circuit the equipment is connected in two two cables, for which the current is divided in each branch, the voltage in all the branches is the same, this type of circuit has the advantage that if one equipment is damaged or disconnects the others they can continue working
V_total = V
Therefore, in consequence of the above, the selected configuration is PARALLEL
Answer:
Pressure of gas A = 544.324 kPa
Pressure of gas B = 2217.784 kPa
Explanation:
Data provided in the question:
Total volume of the cylinder, V = 5.55 L = 0.00555 m³ [1 m³ = 1000 L]
Moles on gas A,
= 1.21 mol
Moles on gas A,
= 4.93 mol
Temperature, T = 27.3°C = 27.3 + 273 = 300.3 K
Now,
Pressure = ![\frac{nRT}{V}](https://tex.z-dn.net/?f=%5Cfrac%7BnRT%7D%7BV%7D)
here,
R is the ideal gas constant = 8.314 J/mol.K
Therefore,
Pressure of gas A = ![\frac{n_aRT}{V}](https://tex.z-dn.net/?f=%5Cfrac%7Bn_aRT%7D%7BV%7D)
= ![\frac{1.21\times8.314\times300.3}{0.00555}](https://tex.z-dn.net/?f=%5Cfrac%7B1.21%5Ctimes8.314%5Ctimes300.3%7D%7B0.00555%7D)
= 544324.32 Pa
= 544.324 kPa
Pressure of gas B =
= ![\frac{4.93\times8.314\times300.3}{0.00555}](https://tex.z-dn.net/?f=%5Cfrac%7B4.93%5Ctimes8.314%5Ctimes300.3%7D%7B0.00555%7D)
= 2217784.22 Pa
= 2217.784 kPa