Answer:
2 m/s and -2 m/s
Explanation:
The object travels with an angle of
60.0°
with the positive direction of the y-axis: this means that it lies either in the 1st quadrant (positive x) or in the 2nd quadrant (negative x).
If it lies in the 1st quadrant, the value of vx (component of v along x direction) is:
If it lies in the 2nd quadrant, the value of vx (component of v along x direction) is:
Answer:
a) 0.00996 m
b) 109090909 Pa
Explanation:
Unit conversions:
1.2 mm = 0.0012 m
8.5 kN = 8500 N
If the 2.2m rod cannot stretch more than 0.0012 m, its maximum strain is
With elastic modulus being E = 200 GPa, then its maximum stress must be
Knowing the tension force being F = 8500 N, we can calculate the appropriate cross section area
And its corresponding diameter is
Answer:
Explanation:
The density of an object is given by
where
m is the mass of the object
V is its volume
In this problem,
m = 42 kg
V = 22 m^3
Substituting into the equation, we find the object's density:
Answer:
0.5504
Explanation:
We can use Bay's theorem to solve this question
P( No physics career/fail) = P(No Physics career and fail)/P(Fail)
= P( Fail/ No physics career)×P( no physics career)/P( fail)
=
=0.5504