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2 years ago

A substance that reduces the hydrogen ion concentration of a solution is __________.

Chemistry

1 answer:

ioda2 years ago

8 0

A substance that reduces the hydrogen ion concentration of a solution is base.

A base which thus completely dissociates in an aqueous solution is referred to as a strong base. These substances produce one or more hydroxide ions (OH-) per base molecule when they ionize in water. A weak base, on the other hand, only partially splits into its water-soluble ions.

The three definitions of "base" used in chemistry are Arrhenius base, Bronsted base, as well as Lewis base. The fact instead that bases react towards acids is acknowledged by all base definitions.

Therefore, a substance that reduces the hydrogen ion concentration of a solution is base.

To know more about hydrogen ion

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Consider two different ions. The anion has a valence of -2. The cation has a valence of +2. The two ions are separated by a dist

strojnjashka [21]

Answer:

Force of attraction = 35.96 $\times 10^{27}$ N

Explanation:

Given: charge on anion = -2

Charge on cation = +2

Distance = 1 nm = $10^{-9}$ m

To calculate: Force of attraction.

Solution: The force of attraction is calculated by using equation,

$F = \dfrac{k \times q_1 q_2}{ \r^2}$ ---(1)

where, q represents the charge and the subscripts 1 and 2 represents cation and anion.

k = $8.99 \times 10^9 \ Nm^{2}C^{-2}$

F = force of attraction

r = distance between ions.

Substituting all the values in the equation (1) the equation becomes

$F = \dfrac{8.99 \times 10^9 \times 2 \times 2}{ \left ( 10^-9 \right )^2 }$

Force of attraction = 35.96 $\times 10^{27}$ N

6 0

3 years ago

Which element would be expected to have chemical and physical properties closest to those of rubidium?

DIA [1.3K]

Rubidium is an element that belongs to Group 1. As such it will have physical properties similar to the other Group 1 elements. Rubidium is below Potassium in the periodic table but above Cesium. As such it would be most like one of those two elements.

7 0

3 years ago

A 25.0-mL sample of 0.150 M hydrocyanic acid is titrated with a 0.150 M NaOH solution. The Ka of hydrocyanic acid is 4.9 × 10-10

lara [203]

Answer:

The pOH = 1.83

Explanation:

Step 1: Data given

volume of the sample = 25.0 mL

Molarity of hydrocyanic acid = 0.150 M

Molarity of NaOH = 0.150 M

Ka of hydrocyanic acid = 4.9 * 10^-10

Step 2: The balanced equation

HCN + NaOH → NaCN + H2O

Step 3: Calculate the number of moles hydrocyanic acid (HCN)

Moles HCN = molarity * volume

Moles HCN = 0.150 M * 0.0250 L

Moles HCN = 0.00375 moles

Step 3: Calculate moles NaOH

Moles NaOH = 0.150 M * 0.0305 L

Moles NaOH = 0.004575 moles

Step 4: Calculate the limiting reactant

0.00375 moles HCN will react with 0.004575 moles NaOH

HCN is the limiting reactant. It will completely be reacted. There will react 0.00375 moles NaOH. There will remain 0.004575 - 0.00375 = 0.000825 moles NaOH

Step 5: Calculate molarity of NaOH

Molarity NaOH = moles NaOH / volume

Molarity NaOH = 0.000825 moles / 0.0555 L

Molarity NaOH = 0.0149 M

Step 6: Calculate pOH

pOH = -log [OH-]

pOH = -log (0.0149)

pOH = 1.83

The pOH = 1.83

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3 years ago

A base

hichkok12 [17]

B, turns red litmus paper to blue

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3 years ago

An aircraft is taking a group of skydivers up into the air. Evan is dressed in

Kisachek [45]

4,410 kJ

Explanation:

Gravitational Potential Enegry (GPE) is calculated as;

GPE = m*g*h where;

m = mass (kg)

g = gravity (m/s²)

h = height (meters)

= 90 * 9.8 * 5000

= 4,410,000‬ joules

= 4,410 kJ

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3 years ago