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1 year ago

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Which forces are intramolecular and which intermolecular?

1 answer:

xxTIMURxx [149]1 year ago

5 0

On a chilly, humid evening, intermolecular forces enable fog to form. The gaseous water molecules condense as a result of powerful molecular interactions.

What force allows fog formation?

From the south, warm, moist air is brought in, and if there is snow or cool precipitation on the ground, it will come into touch with the warm, moist breezes. The air coming in will cool as a result of this air-ground contact. Dew point rises at that position, leading to high humidity and the formation of fog.

What is molecular interactions?

Interactions between molecules or between atoms without bonds are referred to as molecular interactions. There are three types of molecular interactions: cohesive (attraction between like), adhesive (attraction between unlike), and repulsive forces.

Learn more about molecular interactions: brainly.com/question/20910897

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A tank at is filled with of sulfur tetrafluoride gas and of sulfur hexafluoride gas. You can assume both gases behave as ideal g

dangina [55]

The question is incomplete, the complete question is:

A 7.00 L tank at $21.4^oC$ is filled with 5.43 g of sulfur hexafluoride gas and 14.2 g of sulfur tetrafluoride gas. You can assume both gases behave as ideal gases under these conditions. Calculate the mole fraction and partial pressure of each gas. Round each of your answers to significant digits.

<u>Answer:</u> The mole fraction of sulfur hexafluoride is 0.221 and that of sulfur tetrafluoride is 0.779

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

<u>For sulfur hexafluoride:</u>

Given mass of sulfur hexafluoride = 5.43 g

Molar mass of sulfur hexafluoride = 146.06 g/mol

Putting values in equation 1, we get:

$\text{Moles of sulfur hexafluoride}=\frac{5.43g}{146.06g/mol}=0.0372mol$

<u>For sulfur tetrafluoride:</u>

Given mass of sulfur tetrafluoride = 14.2 g

Molar mass of sulfur tetrafluoride = 108.07 g/mol

Putting values in equation 1, we get:

$\text{Moles of sulfur tetrafluoride }=\frac{14.2g}{108.07g/mol}=0.1314mol$

Total moles of gas in the tank = [0.0372+ 0.1314] mol = 0.1686 mol

Mole fraction is defined as the moles of a component present in the total moles of a solution. It is given by the equation:

$\chi_A=\frac{n_A}{n_A+n_B}$ .....(2)

where n is the number of moles

Putting values in equation 2, we get:

$\chi_{SF_6}=\frac{0.0372}{0.1686}=0.221$

$\chi_{SF_4}=\frac{0.1314}{0.1686}=0.779$

Hence, the mole fraction of sulfur hexafluoride is 0.221 and that of sulfur tetrafluoride is 0.779

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The table below compares the radioactive decay rates of two materials. Material Original mass of material (in grams) Mass of mat

Dmitry [639]

Answer:

The half-life of Material 1 and Material 2 are equal.

step by step explanation;

Material 1 disintegrates to half its mass three times in 21.6 s, to go from 100g

to 12.5g. That is,

100g - 50g - 25g - 12.5g

Material 2 disintegrates to half its mass three times in 21.6 s, to go from 200g to 25g. That is,

200g - 50g - 25g - 12.5g.

This means that regardless of their initial masses involved, material 1 and material 2 have equal half-life.

Their half-life is 21.6 ÷ 3 = 7.2 sec

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