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allsm [11]
1 year ago
10

3.The simplest way of separating visible solid impurities that do not dissolve in water from water

Chemistry
1 answer:
stiv31 [10]1 year ago
3 0

The simplest way of separating visible solid impurities that do not dissolve in water from water is by using a sieve (option A).

<h3>What is sieving?</h3>

Sieving is a act of passing substances through a sieve, which is a device with a mesh bottom to separate, in a granular material, larger particles from smaller ones, or to separate solid objects from a liquid.

Sieving is a physical method of separation widely used to separate substances that cannot dissolve in a liquid from that liquid.

Therefore, the simplest way of separating visible solid impurities that do not dissolve in water from water is by using a sieve.

Learn more about sieving at: brainly.com/question/2760394

#SPJ1

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Which of the following is NOT soluble in water?
raketka [301]
The correct answer is E. C6H6 is not soluble in water. This is determined by the polarities of these substances. Benzene is a non-polar substance because it has equal number of electrons sharing a bond thus it does not dissolve in water which is a polar substance.
7 0
3 years ago
Read 2 more answers
A sample of He at 25C and 755 torr occupies a fixed volume of 16.8L. What mass of He must be pumped in to increase the pressure
AURORKA [14]

Answer:

2.4 g

Explanation:

Step 1: Given data

  • Initial pressure (P₁): 755 torr
  • Volume (V): 16.8 L
  • Temperature (T): 25 °C
  • Final pressure (P₂): 1.87 atm

Step 2: Convert "P₁" to atm

We will use the conversion factor 1 atm = 760 torr.

755 torr × 1 atm/760 torr = 0.993 atm

Step 3: Convert "T" to K

We will use the following expression.

K = °C + 273.15

K = 25°C + 273.15 = 298 K

Step 4: Calculate the initial number of moles of He

We will use the ideal gas equation.

P₁ × V = n₁ × R × T

n₁ = P₁ × V/R × T

n₁ = 0.993 atm × 16.8 L/(0.0821 atm.L/mol.K) × 298 K

n₁ = 0.682 mol

Step 5: Calculate the final number of moles of He

We will use the ideal gas equation.

P₂ × V = n₂ × R × T

n₂ = P₂ × V/R × T

n₂ = 1.87 atm × 16.8 L/(0.0821 atm.L/mol.K) × 298 K

n₂ = 1.28 mol

Step 6: Calculate the moles of He added

n = n₂ - n₁

n = 1.28 mol - 0.682 mol

n = 0.60 mol

Step 7: Convert "n" to mass

The molar mass of He is 4.00 g/mol

0.60 mol × 4.00 g/mol = 2.4 g

8 0
3 years ago
Where does the majority of drinking water come from in rural areas in North Carolina?
kupik [55]
A, ground water. (filler for the 20 character)
3 0
3 years ago
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Consider the balanced equation for the following reaction:
WITCHER [35]

Answer:

In this reaction HCl is the limiting reactant and aluminium is the reactant in excess.

Explanation:

Step 1: Data given

Mass of HCl = 69.0 grams

Mass of Al = 78.0 grams

Molar mass HCl = 36.46 g/mol

Atomic mass Al = 26.99 g/mol

Step 2: The balanced equation

6HCl(aq) + 2Al(s) → 3H2(g) + 2AlCl3(s)

Step 3: calculate moles HCl

Moles HCl = mass HCl / molar mass HCl

Moles HCl = 69.0 grams / 36.46 g/mol

Moles HCl = 1.89 moles

Step 4: Calculate moles Al

Moles Al = 78.0 grams / 26.99 g/mol

Moles Al = 2.89 moles

Step 5: Calculate the limiting reactant

For 6 moles HCl we need 2 moles Al  to produce 3 moles H2 and 2 moles AlCl3

HCl is the limiting reactant. It will completely be consumed (1.89 moles). Aluminium is the reactant in excess. There will react 1.89 / 3 = 0.63 moles

There will remain 2.89 - 0.63 = 2.26 moles aluminium

In this reaction HCl is the limiting reactant and aluminium is the reactant in excess.

7 0
3 years ago
A 15.0 L tank of gas is contained at a high pressure of 8.20x10 4 torr. The tank is opened and the gas expands into an empty cha
Alexxx [7]

Answer:

P₂ = 20.5 torr

Explanation:

Given data:

Volume of tank = 15.0 L

Pressure of tank = 8.20×10⁴ torr

Final volume of tank = 6.00×10⁴ L

Final pressure = ?

Solution:

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

8.20×10⁴ torr  ×  15.0 L = P₂ × 6.00×10⁴ L

P₂ = 8.20×10⁴ torr  ×  15.0 L / 6.00×10⁴ L

P₂ = 123×10⁴ torr.L/ 6.00×10⁴ L

P₂ = 20.5 torr

7 0
3 years ago
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