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tatiyna
2 years ago
3

How does the variation in atomic size across a transition series contrast with the change across the main-group elements of the

same period? Why?
Chemistry
1 answer:
Dmitry [639]2 years ago
3 0

The atomic and ionic radii of the transition elements decrease from group 3 to group 6 due to the poor shielding offered by the small number of d-electrons. Those placed between groups 7 and 10 have somewhat similar atomic radii and those placed in groups 11 and 12 have larger radii. This is because the nuclear charge is balanced out by the electron-electron repulsions.

<h3>What is transition elements?</h3>

Transition elements or transition metals are elements that have partially filled d orbitals.

"Transition elements as an element having a d subshell that is partially filled with electrons, or an element that has the ability to form stable cations with an incompletely filled d orbital".

In general, any element which corresponds to the d-block of the modern periodic table (groups 3-12) is considered to be a transition element.

To learn more about transition elements, refer

brainly.com/question/23094060

#SPJ4

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Calculate the time,speed is 100 m/s and distance is 2000 meter.​
borishaifa [10]

Answer:

Speed = distance /time

Explanation:

Time = distance /speed

Hence.

S=100

D=2000

There fore time is... 20 sec

3 0
3 years ago
2. Which element below would be the best choice when creating a covalent molecule with an
sammy [17]

Answer:

The chemical elements most likely to form covalent bonds are those that share electrons, such as carbon, as opposed to those that take them from another element to form an ionic bond. In general, they are nonmetals with similar electronegativities.

Explanation:

3 0
3 years ago
Read 2 more answers
Consider the following unbalanced chemical equation. C5H12(l) + O2(g) → CO2(g) + H2O(l) If 21.9 grams of pentane (C5H12) are bur
Marina CMI [18]

Answer : The mass of water produced will be 32.78 grams.

Explanation : Given,

Mass of C_5H_{12} = 21.9 g

Molar mass of C_5H_{12} = 72.15 g/mole

Molar mass of H_2O = 18 g/mole

First we have to calculate the moles of C_5H_{12}.

\text{Moles of }C_5H_{12}=\frac{\text{Mass of }C_5H_{12}}{\text{Molar mass of }C_5H_{12}}=\frac{21.9g}{72.15g/mole}=0.3035moles

Now we have to calculate the moles of H_2O.

The balanced chemical reaction will be,

C_5H_{12}(l)+8O_2(g)\rightarrow 5CO_2(g)+6H_2O(l)

From the balanced reaction we conclude that

As, 1 mole of C_5H_{12} react to give 6 moles of H_2O

So, 0.3035 moles of C_5H_{12} react to give 0.3035\times 6=1.821 moles of H_2O

Now we have to calculate the mass of H_2O.

\text{Mass of }H_2O=\text{Moles of }H_2O\times \text{Molar mass of }H_2O

\text{Mass of }H_2O=(1.821mole)\times (18g/mole)=32.78g

Therefore, the mass of water produced will be 32.78 grams.

3 0
3 years ago
What is the pH of a solution with a 3.2 x 10−6 M hydronium ion concentration?
Rainbow [258]

Answer:

<h2>5.49</h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log ([ { H_3O}^{+}])

H3O+ is the hydronium ion

From the question we have

pH =  -  log(3.2 \times  {10}^{ - 6} )  \\  = 5.49485..

We have the final answer as

<h3>5.49 </h3>

Hope this helps you

4 0
3 years ago
Draw the product formed when the following diene is treated with one equivalent of HCl. Do not show stereochemistry in your answ
garri49 [273]

Answer:

4-chloro-4-methyl-cyclohexene.

Explanation:

Hello,

On the attached picture you will find the chemical reaction forming the required product, 4-chloro-4-methyl-cyclohexene. In this case, according to the Markovnicov’s rule, it is more likely for the chlorine to be substituted at the carbon containing the methyl radical in addition to the hydrogen to the next carbon to break the double bond and yield the presented product.

Best regards.

6 0
3 years ago
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