Question

Q/C (b) Would a proton traveling at the same speed require a greater or lesser magnitude of electric potential difference? Explain

Answer 1

The electric potential difference $\triangle V_e$ required to stop an electron (called a "stopping potential") moving with an initial speed (v) of 2.85 × 10⁷ m/s is 2.309 $\times10^3V$.

A proton traveling at the same speed require a greater magnitude of electric potential difference.

How to calculate the electric potential difference?

We know, that the kinetic energy is:

$K=qV_0=\frac{1}{2} mv^2$

where,

q is the charge

q=1.6$\times10^{-19}$C

$V_0$ is the stopping potential

m is the mass of the electron

m=9.1$\times10^{-31}$kg

v is the speed of the electron

$V_0=\frac{1}{2}\frac{ mv^2}{q}$

q and v is same for both the proton and the electron.

$V_0$ is greater for proton than the electron this is because of the fact that mass of the proton is greater than the mass of an electron.

To learn more about total electric potential, refer to:

brainly.com/question/16843018

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