1st-B
2nd-A
3rd-C variation in frequency
Answer:
32s
Explanation:
We must establish that by the time the police car catches up to the speeder, both have travelled a certain distance during the same amount of time. However, the police car experiences accelerated motion whereas the speeder travels at a constant velocity. Therefore we will establish two formulas for distance starting with the speeder's distance:
and the police car distance:
Since they both travel the same distance x, we can equal both formulas and solve for t:
Two solutions exist to the equation; the first one being
The second solution will be:
This result allows us to confirm that the police car will take 32s to catch up to the speeder
You want to know the difference between the two velocities, so you have to think 9 m/s - 2 m/s. The result is 7 m/s, the second option of your list. Hope that was helpful, have a great day!
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