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Alex
1 year ago
13

Tiffany has been waiting for weeks to see one particular meteor shower that peaks around august 12. What meteor shower is tiffan

y most likely waiting to see?
Physics
1 answer:
Andru [333]1 year ago
5 0

Tiffany has been waiting for weeks to see one particular meteor shower that peaks around august 12. Tiffany is waiting to see Perseid Meteor Shower.

A very bright supermoon known as a "Sturgeon Moon" may make it difficult for photographers to capture this year's climax of the Perseid Meteor Shower tonight (August 12). The Perseid meteor shower, which peaks overnight on August 12 and 13, is one of the most powerful annual meteor showers and occurs between July 14 and September 1. Unfortunately, that falls on the night of this month's full moon, which became fully illuminated yesterday night (Aug. 11). The meteor shower is named after the constellation, the northern constellation Perseus.

Learn more about Perseid Meteor Shower here:

brainly.com/question/16517600

#SPJ4

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A uniform disk, a thin hoop, and a uniform sphere, all with the same mass and same outer radius, are each free to rotate about a
olga nikolaevna [1]

Answer:

4 hoop, disk, sphere

Explanation:

Because

We are given data that

Hoop, disk, sphere have Same mass and radius

So let

And Initial angular velocity, = 0

The Force on each be F

And Time = t

Also let

Radius of each = r

So let's find the inertia shall we!!

I1 = m r² /2

= 0.5 mr² the his is for dis

I2 = m r² for hoop

And

Moment of inertia of sphere wiil be

I3 = (2/5) mr²

= 0.4 mr²

So

ωf = ωi + α t

= 0 + ( τ / I ) t

= ( F r / I ) t

So we can see that

ωf is inversely proportional to moment of inertia.

And so we take the

Order of I ( least to greatest ) :

I3 (sphere) , I1 (disk) , I2 (hoop) , ,

Order of ωf: ( least to greatest)

That of omega xf is the reverse of inertial so

hoop, disk, sphere

Option - 4

5 0
3 years ago
In which region of the electromagnetic spectrum is most of earth's outgoing terrestrial radiation?
Bond [772]
The answer is Infrared.  The infrared of the electromagnetic spectrum is most of earth's outgoing terrestrial radiation.  <span>Earth is the hot body with temperature of 30 degrees on the average.</span>
6 0
3 years ago
What happens to light waves from a star as the star moves away from Earth?
AURORKA [14]
<h2>Answer: Light waves have a redshift due to the Doppler effect </h2>

The astronomer Edwin Powell Hubble observed several celestial bodies, and when obtaining the spectra of distant galaxies he observed the spectral lines were displaced towards the red (red shift), whereas the nearby galaxies showed a spectrum displaced to the blue.  

From there, Hubble deduced that the farther the galaxy is, the more redshifted it is in its spectrum. <u>The same happens with the stars and this phenomenom is known as the Doppler effect. </u>

This phenomenon refers to the change in a wave perceived frequency (or wavelength=color) when the emitter of the waves, and the receiver (or observer in the case of light) move relative to each other.  For example, as a star moves away from the Earth, its espectrum turns towards the red.

8 0
3 years ago
Tarzan has foolishly gotten himself into another scrape with the animals and must be rescued once again by Jane. The 60.0 kg Jan
Brut [27]

Complete part of Question: What is Jane's (and the vine's) angular speed just before she grabs Tarzan

Answer:

Jane's (and the vine's) angular speed just before she grabs Tarzan, w = 1.267 rad/s

Explanation:

According to the law of energy conservation:

Total change in kinetic energy = Total change in potential energy

Mass of Jane = 60 kg

Mass of the vine = 32 kg

Mass of Tarzan = 72 kg

Height of Tarzan = 5.50 m

Length of the vine = 8.50 m

Jane's change in gravitational potential energy,

U_J = 60 * 9.8 * 5.5\\U_J = 3234 J

Vine's gravitational potential energy,

U_v = Mgh/2\\U_v = 32*9.8*5.5/2\\U_v = 862.4J

Vine's Kinetic energy :

KE_V = 0.5 I w^{2} \\I_V = \frac{ML^2}{3} = \frac{32 * 8.5^2}{3} = 770.67 kg m^2\\ KE_V = 0.5 *770.67 * w^{2}\\KE_V = 385.33 w^{2}

Jane's Kinetic energy:

KE_J = 0.5m(wL)^2\\KE_J = 0.5*60(w * 8.5)^2\\KE_J = 2167.5 w^2

U_J + U_V = KE_J + KE_V

3234 + 862.4 = 2167.5w² + 385.33w²

4096.4 = 2552.83w²

w² = 4096.4/2552.83

w² = 1.605

w = √1.605

w = 1.267 rad/s

5 0
3 years ago
Apply a force of 50N to the left describe the motion of the box
GenaCL600 [577]
When a force is applied to the box , this will cause an acceleration to the box.
(force =mass×acceleration)

So the box has a constant acceleration and a changing velocity.
4 0
3 years ago
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