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Nutka1998 [239]
2 years ago
5

What application of bioengineering uses principles of electronics and computer science to design products?

Engineering
1 answer:
Flauer [41]2 years ago
4 0

The application of electro bioengineering uses principles of nick and computer science to design products is application of electrical engineering principles to biology, medicine, conduct, or health.

<h3>What is Bioelectronics?</h3>
  • Bioelectronics is the application of electrical engineering principles to biology, medicine, conduct, or health.
  • It advances the fundamental concepts, creates knowledge for the molecular to the organ techniques levels, and develops creative devices or methods for the deterrence, diagnosis, and treatment of disease, for patient rehabilitation, and for improving health.
  • Bio electromagnetics, instrumentation, neural networks, robotics, and detector technologies are some of the disciplines necessary to develop new knowledge and creations in this area.
  • A keystone of this research area is the building of and real-world devices and systems.
  • Onsite facilities for prototyping and testing instrumentation systems, fabricating and measuring the performance of implantable devices, and making robotic prostheses, are readily available.
  • New detectors and sensor arrays are microfabricated in a 2,000 sq ft cleanroom.

To learn more about Bioelectronics, refer to:

brainly.com/question/21819443

#SPJ4

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Consider steady heat transfer through the wall of a room in winter. The convection heat transfer coefficient at the outer surfac
AveGali [126]

The heat transfer which is in steady state, the heat transfer rate to the wall is equal to the wall.

<u>Explanation:</u>

  • The convection transfer of heat to the wall is

         Q=h A\left(T_{s}-T_{f}\right)

  • Here, T_{S} is the temperature of solid surface, T_{f} is the temperature of moving fluid stream which is adjacent of solid surface, h is the heat transfer coefficient.
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Dimensioning a drawing means​
lara [203]

Answer:

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<em>Hope it helps <3</em>

7 0
3 years ago
A one-dimensional slab without heat generation has a thickness of 20 mm with surfaces main- tained at temperatures of 275 K and
vlada-n [284]

Answer:

a) 512.5 KW/m2

b) 40.75 KW/m2

c) 2 KW/m2

Explanation:

Given data;

T_2 = 325 K

T_1 = 275 K

dx = 0.20 mm

a) for aluminium   K = 205 W/m k

heat flux = k \frac{dt}{dx}

               = 205 \frac{325 - 275}{0.02}

               = 512.5 KW/m2

b) for AISI 316 stainless steel

k = 16.3 W/ m k

heat flux = k \frac{dt}{dx}

               = 16.3 \frac{325 - 275}{0.02}

               = 40.75 KW/m2

C) for Concrete

k = 0.8 W/ m k

heat flux = k \frac{dt}{dx}

               = 0.8 \times \frac{325 - 275}{0.02}

               = 2 KW/m2

6 0
3 years ago
For some transformation having kinetics that obey the Avrami equation , the parameter n is known to have a value of 1.1. If, aft
ivanzaharov [21]

Answer:

total time  = 304.21 s

Explanation:

given data

y = 50% = 0.5

n = 1.1

t = 114 s

y = 1 - exp(-kt^n)

solution

first we get here k value by given equation

y = 1 - e^{(-kt^n)}   ...........1    

put here value and we get

0.5 = 1 - e^{(-k(114)^{1.1})}    

solve it we get

k = 0.003786  = 37.86 × 10^{4}

so here

y = 1 - e^{(-kt^n)}

1 - y  =  e^{(-kt^n)}

take ln both side

ln(1-y) = -k × t^n  

so

t = \sqrt[n]{-\frac{ln(1-y)}{k}}    .............2

now we will put the value of y = 87% in equation  with k and find out t

t = \sqrt[1.1]{-\frac{ln(1-0.87)}{37.86*10^{-4}}}

total time  = 304.21 s

7 0
3 years ago
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