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poizon [28]
1 year ago
11

Structural, electronic, and thermodynamic properties of TiO$_{2}$/organic clusters: performance of DFTB method with different pa

rameter sets
Chemistry
1 answer:
Sladkaya [172]1 year ago
4 0

A second-order extension of the Kohn-Sham total energy in density-functional theory (DFT) with respect to charge density fluctuations serves as the foundation for the density functional based tight binding (DFTB) approach.

What is DFTB method?

  • The density functional based tight binding (DFTB) electronic structure method was used to study the clusters of bare TiO2 and TiO2 with linked organic ligands modeling polyorganic composites used as photocatalytic materials.
  • The results were compared to those obtained from B3LYP/6-31G(d,p) calculations, semiempirical methods PM6 and PM7, and available experimental data.
  • It was discovered that the highly scalable DFTB approach produces outcomes that are nearly on the level of theory B3LYP/6-31G(d,p).
  • The trans3d set more accurately reproduces the energies of the composite material production in polycondensation processes, but the corrected version of the tiorg DFTB parameter set (tiorg-smooth) performs better for structural parameter estimations.
  • The tiorg-smooth and trans3d settings perform better than the matsci set in some way. Studies of adsorption complexes of bare TiO2 clusters can be conducted using the tiorg-smooth and matsci sets.

Learn more about the Density with the help of the given link:

brainly.com/question/23487480

#SPJ4

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The empirical formula of an organic compound is C2H4O. The molecular mass of the compound is 176g/mol.
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Answer:

The molecular formula of the compound is C_{8}H_{16}O_{4}. The molecular formula is obtained by the following expression shown below

\textrm{Molecular formula }= n\times \textrm{Empirical formula}

Explanation:

Given molecular mass of the compound is 176 g/mol

Given empirical formula is  C_{2}H_{4}O

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n = \displaystyle \frac{\textrm{Molecular formula mass}}{\textrm{Empirical formula mass}} \\n = \displaystyle \frac{176}{44} = 4

\textrm{Molecular formula }= n\times \textrm{Empirical formula}

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Molecular formula is C_{8}H_{16}O_{4}

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