Answer:
Molecular formula = C₂H₆
Explanation:
Given data:
Percentage of hydrogen = 20.0 %
Percentage of carbon = 80.0 %
Molar mass = 30.0 g
Empirical formula = ?
Solution:
Number of gram atoms of H = 20 / 1.01 = 19.8
Number of gram atoms of C = 80 /12 = 6.7
Atomic ratio:
C : H
6.7/6.7 : 19.8/6.7
1 : 3
C : H = 1 : 3
Empirical formula is CH₃.
Molecular formula:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula = CH₃ = 12×1 +3×1.01 = 15.03 g/mol
n = 30 g/mol / 15.03 g/mol
n = 2
Molecular formula = n (empirical formula)
Molecular formula = 2 (CH₃)
Molecular formula = C₂H₆
Correct me if I am wrong but I believe the answer is in order of the numbered statements
6, 7, 1, 4, 3, 5, 2
Moles of Na_2O
- Given mass/Molar mass
- 35/62
- 0.56mol
2 mols Na_2O produces 1 mol sodium carbonate.
1 mol sodium oxide produces 0.5mol sodium carbonate
Moles of sodium carbonate
Molar mass
- 2(23)+12+3(16)
- 46+12+48
- 106g/mol
Mass
Answer: 24.13 g Cu
Explanation:
<u>Given for this question:</u>
M of CuO = 30 g
m of CuO = 79.5 g/mol
Number of moles of CuO = (given mass ÷ molar mass) = (30 ÷ 79.5) mol
= 0.38 mol
The max number of CuO (s) that can be produced by the reaction of excess methane can be solved with this reaction:
CuO(s) + CH4(l) ------> H2O(l) + Cu(s) + CO2(g)
The balanced equation can be obtained by placing coefficients as needed and making sure the number of atoms of each element on the reactant side is equal to the number of atoms of each element on the product side
4CuO(s) + CH4(l) ----> 2H2O(l) + 4Cu(s) + CO2(g)
From the stoichiometry of the balanced equation:
4 moles of CuO gives 4 moles of Cu
1 mole of CuO gives 1 mol of Cu
0.38 mol of CuO gives 0.38 mol of Cu
Therefore, the grams of Cu that can be produced = 0.38 × molar mass of Cu
= 0.38 × 63.5 g
= 24.13 grams
Therefore, 24.13 grams of copper could be produced by the reaction of 30.0 of copper oxide with excess methane
Three
A typical atom consists of three subatomic particles: protons, neutrons, and electrons (as seen in the helium atom below). Other particles exist as well, such as alpha and beta particles (which are discussed below). The Bohr model shows the three basic subatomic particles in a simple manner.
