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tester [92]
3 years ago
6

.950 L of .420 M H2SO4 is mixed with .900 L of .260 M KOH. What concentration of sulfuric acid remains after neutralization?

Chemistry
1 answer:
kipiarov [429]3 years ago
3 0
H₂SO₄:

V=0,95L
Cm=0,420mol/L

n = CmV = 0,42mol/L * 0,95L = 0,399mol

KOH:

V=0,9L
Cm=0,26mol/L

n = CmV = 0,26mol/L * 0,9L = 0,234mol

H₂SO₄            +           2KOH ⇒ K₂SO₄ + 2H₂O
1mol                :           2mol
0,399mol         :           0,234mol
                                    limiting reagent
reamins: 0,399mol - 0,117mol = 0,282mol

n = 0,282mol
V = 0,950L + 0,900L = 1,85L

Cm = n / V = 0,282mol / 1,85L ≈ 0,152M
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Answer:4

Explanation:

As shown in the image attached, a face-centred cubic structure has 8 atoms at the corners and 6 face center atoms.

Each corner atom contributes to eight cell, so per unit cell 1/8 ×8 =1atom

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7 0
3 years ago
13) Find the mass, in grams, of 5.75 liters of N2.
faltersainse [42]
Molecular weight of N2
gram Atomic weight of N is 14 g.
gram Molecular weight = 14 g×2
= 28 g
Liter concepts
1 liter of gas always occupies 1 gram molecular weight .
Application of the concept
5.75 liter gives 0.257g


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0.257 will occupy 28 g × 0.257
= 7.196 g

The mass of the gas is 7.196 g.

Hope it helps you
8 0
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Initially, scientists described atoms as the smallest particles of matter. However, smaller particles within atoms were discover
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By designing new technology that would prove new information

Explanation:

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3 years ago
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How can you tell that a gas is a halogen? ___?
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8 0
3 years ago
Calculate the number of moles of NaOH contained in 250. mL of a 0.05M solution.
steposvetlana [31]

Answer:

0.0125mol

Explanation:

Molarity (M) = number of moles (n) ÷ volume (V)

n = Molarity × Volume

According to this question, a 0.05M solution contains 250 mL of NaOH. The volume in litres is as follows:

1000mL = 1L

250mL = 250/1000

= 0.250L

n = 0.05 × 0.250

n = 0.0125

The number of moles of NaOH is 0.0125mol.

3 0
3 years ago
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