Answer:
Reactants: Ethanol (C₅H₅OH), Oxygen (O₂)
Products: Carbon dioxide (CO₂) and Water (H₂O)
Explanation:
Let’s rewrite each part of the described situation in chemical equation terms.
Ethanol - C₂H₅OH
is burned in the prescence of - +
oxygen - O₂
producing - →
carbon dioxide - CO₂
and - +
water - H₂O
Chemical equation:
C₂H₅OH + O₂ → CO₂ + H₂O
The terms on the left side of a chemical equation are reactants, and the terms on the right side of a chemical equation are products.
Therefore, since we know this, ethanol (C₂H₅OH) & oxygen (O₂) are the reactants, and carbon dioxide (CO₂) & water (H₂O) are the products.
2KOH + Cu(NO3)2 → 2KNO3 + Cu(OH)2
2K⁺ 1Cu²⁺ 2K⁺ 1Cu²⁺
2OH ⁻ 2NO3⁻ 2NO3⁻ 2OH⁻
<span>Molarity is expressed as
the number of moles of solute per volume of the solution. We calculate as follows:
2.80 g ( 1 mol / 56.11 g ) = 0.05 mol KOH
Molarity = 0.05 mol KOH / 750 mL ( 1 L / 1000 mL )
Molarity = 0.07 M
Hope this answers the question. Have a nice day.</span>
the correct answer would be the sun
Answer:
Iron remains = 17.49 mg
Explanation:
Half life of iron -55 = 2.737 years (Source)
Where, k is rate constant
So,
The rate constant, k = 0.2533 year⁻¹
Time = 2.41 years
![[A_0]](https://tex.z-dn.net/?f=%5BA_0%5D)
= 32.2 mg
Using integrated rate law for first order kinetics as:
![[A_t]=[A_0]e^{-kt}](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5BA_0%5De%5E%7B-kt%7D)
Where,
![[A_t]](https://tex.z-dn.net/?f=%5BA_t%5D)
is the concentration at time t
is the initial concentration
So,
![[A_t]=32.2\times e^{-0.2533\times 2.41}\ mg](https://tex.z-dn.net/?f=%5BA_t%5D%3D32.2%5Ctimes%20e%5E%7B-0.2533%5Ctimes%202.41%7D%5C%20mg)
![[A_t]=32.2\times e^{-0.610453}\ mg](https://tex.z-dn.net/?f=%5BA_t%5D%3D32.2%5Ctimes%20e%5E%7B-0.610453%7D%5C%20mg)
![[A_t]=17.49\ mg](https://tex.z-dn.net/?f=%5BA_t%5D%3D17.49%5C%20mg)
<u>Iron remains = 17.49 mg</u>
