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lilavasa [31]
1 year ago
12

explain why a prefabricated steel stair is most commonly used even in buildings that are built with a reinforced concrete frame

structure.
Engineering
1 answer:
Shalnov [3]1 year ago
3 0

Steel can support a lot of weight and is nearly five times as robust as concrete. A steel staircase may be constructed with a lot less material than a concrete one and is stronger than a concrete one.

Concrete has a high compression strength, which means it can withstand being forced together with force. The most common material used to build a stairway is concrete because of its exceptional ability to be shaped into any complex design. Timber will always be susceptible to damage from the elements and wood-eating insects, regardless of how much chemical treatment it receives. Rain and snow can quickly deteriorate a wooden staircase if it is outside.

Learn more about concrete here-

brainly.com/question/29616967

#SPJ4

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Assuming the transition to turbulence for flow over a flat plate happens at a Reynolds number of 5x105, determine the following
torisob [31]

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Assuming the transition to turbulence for flow over a flat plate happens at a Reynolds number of 5x105, determine the following for air at 300 K and engine oil at 380 K. Assume the free stream velocity is 3 m/s.

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The transition from the lamina to turbulent begins when the critical Reynolds

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(a).  \;\text{Rex}_{cr}=5 \times 10^5\\\\\frac{\rho\;vx}{\mu}=5 \times 10^5\\\text{density of of air at}\;300K=1.16  \frac{kg}{m\cdot s}\\\text{viscosity of of air at}\;300K=1.846 \times 10^{-5} \frac{kg}{m\cdot s} \\v=3m/s\\\Rightarrow x=\frac{5\times 10^5 \times 1.846 \times 10^{-5} }{1.16 \times 3} =2.652 \;m \;\text{for air}\\(\text{similarly for engine oil at 380 K for given}\; \rho \;\text{and} \;\mu)\\

(b).\; \text{For the lamina boundary layer momentum boundary layer thickness is given by}:\\\frac{\delta}{x} =\frac{5}{\sqrt{R_e}}\;\;\;\;\quad\text{for}\; R_e(c). \frac{\delta}{\delta_t}={P_r}^{\frac{r}{3}}\\\text{For air} \;P_r \;\text{equivalent 1 hence both momentum and heat dissipate with the same rate for oil}\; \\P_r >>1 \text{heat diffuse very slowly}\\\text{So heat transfer rate will be high for air.}\\\text{Convective heat transfer coefficient will be high for engine oil.}

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