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kumpel [21]
1 year ago
7

How much time would it take a ball to roll 20 yards if it is rolling 4yds/min?

Physics
1 answer:
LekaFEV [45]1 year ago
4 0

speed rate = 4 yards per minute (yds/min)

Distance = 20 yards

time = t

Apply the formula:

time = Distance / speed rate

Replacing:

Time = 20 yards / 4 yds/min = 5 minutes

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D<br>Iylpst any three properties of 9.​
blsea [12.9K]

Answer:Commutative property of multiplication: Changing the order of factors does not change the product. For example, 4 \times 3 = 3 \times 44×3=3×44, times, 3, equals, 3, times, 4.

Associative property of multiplication: Changing the grouping of factors does not change the product. For example, (2 \times 3) \times 4 = 2 \times (3 \times 4)(2×3)×4=2×(3×4)left parenthesis, 2, times, 3, right parenthesis, times, 4, equals, 2, times, left parenthesis, 3, times, 4, right parenthesis.

Identity property o

Explanation:

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2 years ago
In the stream, water waves bunched up as the water flowed by. As we
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Yea it would be barrier. since the stream has a cover for the water
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2 years ago
Why do we eat today
earnstyle [38]
Because if we don't you'll be hungry, if you don't eat for about a month you'll die
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3 years ago
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A skier leaves the horizontal end of a ramp with a velocity of 25.0 m/s and lands 70.0 m from the base of the ramp. How high is
Valentin [98]

Answer:

<em>The end of the ramp is 38.416 m high</em>

Explanation:

<u>Horizontal Motion </u>

When an object is thrown horizontally with an initial speed v and from a height h, it follows a curved path ruled by gravity.

The maximum horizontal distance traveled by the object can be calculated as follows:

\displaystyle d=v\cdot\sqrt{\frac  {2h}{g}}

If the maximum horizontal distance is known, we can solve the above equation for h:

\displaystyle h=\frac  {d^2g}{2v^2}

The skier initiates the horizontal motion at v=25 m/s and lands at a distance d=70 m from the base of the ramp. The height is now calculated:

\displaystyle h=\frac  {70^2\cdot 9.8}{2\cdot 25^2}

\displaystyle h=\frac  {4900\cdot 9.8}{2\cdot 625}

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8 0
2 years ago
Describe each of Newton’s Laws of Motion in ice skating. What can you design/develop to improve ice skating?
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Newton's three laws of motion can be used to describe the motion of the ice skating.

<h3>Newton's first law of motion</h3>

Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that state unless it is acted upon by an external force.

  • Based on this law, once the ice skating starts, it will continue endlessly unless external force stops it.

<h3>Newton's second law of motion</h3>

Newton's second law of motion states that the force applied to an object is directly proportional to the product of mass and acceleration of an object.

  • Based on this law, the force applied to the ice skating is equal to the product of mass and acceleration of the ice skating.

<h3>Newton's third law of motion</h3>

This law states that action and reaction are equal and opposite.

  • Based on this law, the force applied to the ice skating is equal in magnitude to the reaction of ice.

Learn more about Newton's law here: brainly.com/question/3999427

3 0
2 years ago
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