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1 year ago

What is the mass of a truck if it produces a force of 9,000 N while accelerating at a rate of 6 m/s² ?

Physics

1 answer:

timofeeve [1]1 year ago

3 0

1500 kg is the mass of a truck if it produces a force of 9,000 N while accelerating at a rate of 6 m/s²

F=ma

m=F/a

m= 9,000 N / 6 m/s²

m=1500 kg

In physics, mass is used to convey inertia, a property common to all matter. In essence, it is the resistance of a mass of matter to altering its course or speed in response to the application of a force. The more mass a body has, the less of a change an applied force makes. Using Planck's constant, the kilogram, the ISU's unit of mass, is equivalent to 6.62607015 1034 joule seconds (SI). One kilogram is multiplied by one square meter per second to yield one joule. Since the second and the meter have already been defined in terms of other physical constants, the kilogram is determined by precise measurements of Planck's constant.

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Answer:

$\theta = 0.0022 rad$

$I = 0.000304 I_o$

Explanation:

From the question we are told that

The wavelength of the light is $\lambda = 550 \ nm = 550 *10^{-9} \ m$

The distance of the slit separation is $d = 0.500 \ mm = 5.0 *10^{-4} \ m$

Generally the condition for two slit interference is

$dsin \theta = m \lambda$

Where m is the order which is given from the question as m = 2

=> $\theta = sin ^{-1} [\frac{m \lambda}{d} ]$

substituting values

$\theta = 0.0022 rad$

Now on the second question

The distance of separation of the slit is

$d = 0.300 \ mm = 3.0 *10^{-4} \ m$

The intensity at the the angular position in part "a" is mathematically evaluated as

$I = I_o [\frac{sin \beta}{\beta} ]^2$

Where $\beta$ is mathematically evaluated as

$\beta = \frac{\pi * d * sin(\theta )}{\lambda }$

substituting values

$\beta = \frac{3.142 * 3*10^{-4} * sin(0.0022 )}{550 *10^{-9} }$

$\beta = 0.06581$

So the intensity is

$I = I_o [\frac{sin (0.06581)}{0.06581} ]^2$

$I = 0.000304 I_o$

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3 years ago

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But they should end with the equation

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2 years ago

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Answer:

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Explanation:

From the question we are told that

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So comparing this equation obtained an the given exponential relationship we have that

$n = 17.29$

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