The sun orbits the eth at 2kilogram per sec
Answer:
b
Explanation:
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Answer:
4.45×10¯¹¹ N
Explanation:
From the question given above, the following data were obtained:
Mass of ball (M₁) = 4 Kg
Mass of bowling pin (M₂) = 1.5 Kg
Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²
Distance apart (r) = 3 m
Force of attraction (F) =?
The force of attraction between the ball and the bowling pin can be obtained as follow:
F = GM₁M₂ / r²
F = 6.67×10¯¹¹ × 4 × 1.5 / 3²
F = 4.002×10¯¹⁰ / 9
F = 4.45×10¯¹¹ N
Therefore, the force of attraction between the ball and the bowling pin is 4.45×10¯¹¹ N
Hi hi I hope you know that you have a great time jaha
Answer:
.737 v
Explanation:
Since they are in series....they all have the same current running through them.....find the total resistance to calculate the current:
R = 67 + 83 + 433 + 309 = 892 ohm
V/R = current = 7.92 / 892 = 8.87 mAmps
Now the voltage across ecah resistor is I R
for the second one 8.87 ma * 83 ohm = V = .737 V
