The tension in the cord as the elevator accelerates is 76.59 N.
As the elevator starts from rest with a constant upward acceleration and moves 1 m in the first 1.9 s, if the acceleration of the elevator is a, then:
1m = 1/2 a(1.9)²
⇒ a = 2/(1.9²) = 0.55 m/s².
Mass of the bundle; m = 7.4 kg.
Acceleration due to gravity; g = 9.8 m/s².
So, the tension in the cord as the elevator accelerates is = mg + ma
= m(g+a)
= 7.4 ( 9.8 + 0.55) N.
= 76.59 N.
Hence, the tension in the cord is 76.59 N.
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