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Paraphin [41]
1 year ago
8

The HF bond length is 92 pm, 16% shorter than the sum of the covalent radii of H (37 pm) and F (72 pm). Suggest a reason for thi

s difference. Similar data show that the difference becomes smaller down the group, from HF to HI. Explain.
Chemistry
1 answer:
Elza [17]1 year ago
3 0

Due to electronegativity difference between H and F atom.

<h3>What is the reason for the difference ?</h3>
  • The bond length of HF is 92 pm. It is 16% shorter than the sum of the covalent radii of H (37 pm) and F (72 pm).
  • The shorter of the bond length is due to the difference in electronegativity between H and F atom. The electronegativity of F is 4.0, whereas the electronegativity of H is 2.1.
  • Greater the difference of electronegativity between the bonded atoms, shorter will be the bond length.
  • As  becomes smaller i.e. as we proceed from HF to HI, this effect becomes lessens and bond length will be more predictable.

Thus from the above conclusion we can say the difference in electronegativity between H and F atom this is the reason for shorter bond length of HF.

Learn more about bond length here :

brainly.com/question/13683866

#SPJ4

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Calculate the Ka for a 0.3 M solution of HA (unknown weak acid) if the pH = 3.65. The reaction can be modelled as HA (aq) + H2O
Levart [38]

The Ka : 1.671 x 10⁻⁷

<h3>Further explanation</h3>

Given

Reaction

HA (aq) + H2O (l) ←→ A- (aq) + H3O+ (aq).

0.3 M HA

pH = 3.65

Required

Ka

Solution

pH = - log [H3O+]

\tt [H_3O^+]=10^{-3.65}=2.239\times 10^{-4}

ICE method :

HA (aq)        ←→   A- (aq)    +    H3O+ (aq).

0.3                           0                 0

2.239.10⁻⁴           2.239.10⁻⁴   2.239.10⁻⁴

0.3-2.239.10⁻⁴    2.239.10⁻⁴    2.239.10⁻⁴

\tt Ka=\dfrac{[H_3O^+][A^-]}{[HA]}\\\\Ka=\dfrac{(2.239.10^{-4}){^2}}{0.3-2.239.10^{-4}}\\\\Ka=1.671\times 10^{-7}

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3 years ago
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